1) A block (mass mi) can move horizontally on a smooth surface. A homogeneous rod (mass m2) is connected to the block by a pin. The rod is displaced from its equilibrium position and then released. Find the equations of motion for the special case mi = m2. (mi is the last two digits of the student number for example if student ID is 102560332 then m-32 kg. If the last two digits of the student number is 00 then m-12 kg) m1 2a m2

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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1) A block (mass mi) can move horizontally on a smooth surface. A homogeneous rod (mass m2) is connected
to the block by a pin. The rod is displaced from its equilibrium position and then released. Find the equations
of motion for the special case mi = m2. (mi is the last two digits of the student number for example if student
ID is 102560332 then m-32 kg. If the last two digits of the student number is 00 then mi=12 kg)
2a
m2
Transcribed Image Text:1) A block (mass mi) can move horizontally on a smooth surface. A homogeneous rod (mass m2) is connected to the block by a pin. The rod is displaced from its equilibrium position and then released. Find the equations of motion for the special case mi = m2. (mi is the last two digits of the student number for example if student ID is 102560332 then m-32 kg. If the last two digits of the student number is 00 then mi=12 kg) 2a m2
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