Problem Set D(1) A course repeater claims that his brother who did some Calculus at college years ago, butcurrently on some cough medication, believes that the first derivative of(2x² – 1)(x² + 3)f(x) =4x2х 2х 1[(2x2— 1)(x? + 3)is f'(x)x2 +1[2x2 - 1 х2 + 3 х2 + 1x2 + 1and(x² + 8)7(2 – 3x²)5Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you(x² + 8)7(2 – 3x²)5]14х30хthat the first derivative of g(x) =is g'(x) =+ 8 ' 2 – 3x²]confirm whether his brother is right, wrong or a little tipsy.

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(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x? – 1)(x² + 3), 4х 2х |2x² – 1 x2 + 3 x2 + 1] [(2x2 1) (х2 + 3) x2 +1 2x f(x) = -is f'(x) = x2 +1 and (x² + 8)7 (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 14x 30x [(x² + 8)7 that the first derivative of g(x) is g'(x) = 2 + 8*2– 3x²] [(2 – 3x²)³] %3! confirm whether his brother is right, wrong or a little tipsy.

(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x? – 1)(x² + 3), 4х 2х |2x² – 1 x2 + 3 x2 + 1] [(2x2 1) (х2 + 3) x2 +1 2x f(x) = -is f'(x) = x2 +1 and (x² + 8)7 (2 – 3x²)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 14x 30x [(x² + 8)7 that the first derivative of g(x) is g'(x) = 2 + 8*2– 3x²] [(2 – 3x²)³] %3! confirm whether his brother is right, wrong or a little tipsy.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section5.5: Properties Of Logarithms

Problem 62E

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