(1) A. Using the IP address and subnet mask shown write out the network address: (PLEASE SHOW WORKINGS) 192.149.24.191 = 255.255.255.0 150.203.23.19 = 255.255.0.0 10.10.10.10 = 255.0.0.0 186.13.23.110 = 255.255.255.0 223.69.230.250 = 255.255.0.0
(1) A. Using the IP address and subnet mask shown write out the network address: (PLEASE SHOW WORKINGS) 192.149.24.191 = 255.255.255.0 150.203.23.19 = 255.255.0.0 10.10.10.10 = 255.0.0.0 186.13.23.110 = 255.255.255.0 223.69.230.250 = 255.255.0.0
Principles of Information Security (MindTap Course List)
6th Edition
ISBN:9781337102063
Author:Michael E. Whitman, Herbert J. Mattord
Publisher:Michael E. Whitman, Herbert J. Mattord
Chapter6: Security Technology: Access Controls, Firewalls, And Vpns
Section: Chapter Questions
Problem 13RQ
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Question
(1) A. Using the IP address and subnet mask shown write out the network address: (PLEASE SHOW WORKINGS)
192.149.24.191 =
255.255.255.0
150.203.23.19 =
255.255.0.0
10.10.10.10 =
255.0.0.0
186.13.23.110 =
255.255.255.0
223.69.230.250 =
255.255.0.0
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