(1) A. Using the IP address and subnet mask shown write out the network address: (PLEASE SHOW WORKINGS)     192.149.24.191 =     255.255.255.0    150.203.23.19 =       255.255.0.0    10.10.10.10 =     255.0.0.0    186.13.23.110 =     255.255.255.0    223.69.230.250 =     255.255.0.0

Principles of Information Security (MindTap Course List)
6th Edition
ISBN:9781337102063
Author:Michael E. Whitman, Herbert J. Mattord
Publisher:Michael E. Whitman, Herbert J. Mattord
Chapter6: Security Technology: Access Controls, Firewalls, And Vpns
Section: Chapter Questions
Problem 13RQ
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(1) A. Using the IP address and subnet mask shown write out the network address: (PLEASE SHOW WORKINGS)

    192.149.24.191 =
    255.255.255.0

   150.203.23.19 =
      255.255.0.0

   10.10.10.10 =
    255.0.0.0

   186.13.23.110 =
    255.255.255.0

   223.69.230.250 =
    255.255.0.0

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