Solve number 7. p= 4.00 m%D6. A Norman window has the form of a rectanglesurmounted by a semicircle. Find the dimensions (radius of circular part and height of rectangular part) ofthe window that will admit the most light if the perimeter of the window is 4.00 m. See the figure.Answer: r =h=0.56 m1and which has a slope of ½ if x 20. Use a graphingFind the equation of the line normal to the curve y =2x +1Answer: x- 2y + 2 = 0calculator to sketch the curve and the line.%3D8. Write the equation of the normal line to the curve In x+ ye* = -e at (1,–1) in slope-intercept form(%=.= mx +b) by differentiating the implicit relation.%3D7.

Answered: Image /qna-images/answer/7651a00f-5d83-49a2-81e2-85f7aa804ac3.jpg

Answered: 1 and which has a slope of ½ if x >0.…

1 and which has a slope of ½ if x >0. Use a graphing 7. Find the equation of the line normal to the curve y 2x +1 Answer: x- 2y + 2 0 calculator to sketch the curve and the line.

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter1: Equations And Graphs

Section: Chapter Questions

Problem 8T

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

Question

Solve number 7.

p= 4.00 m
%D
6. A Norman window has the form of a rectangle
surmounted by a semicircle. Find the dimensions (radius of circular part and height of rectangular part) of
the window that will admit the most light if the perimeter of the window is 4.00 m. See the figure.
Answer: r =h=0.56 m
1
and which has a slope of ½ if x 20. Use a graphing
Find the equation of the line normal to the curve y =
2x +1
Answer: x- 2y + 2 = 0
calculator to sketch the curve and the line.
%3D
8. Write the equation of the normal line to the curve In x+ ye* = -e at (1,–1) in slope-intercept form
(%=.
= mx +b) by differentiating the implicit relation.
%3D
7.

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