# 1 b) An allele for coat color in mice, Y, produces a yellow coat color when present. The phenotypes of the F1 generation are shown. A cross between a Non-yellow mouse and yellow mouse produces half yellow and half non-yellow progeny (offsprings). Non-yellow happens to be white in this example, but it does not need to be; it can be black, grey, or some other mouse color. How does the F1 generation ratio differ from the expected mendelian ratios for a heterozygous, hybrid cross? * generation Yellow Non-yellow Yellow Yellow Gametes Meiosis Fertilization 1/2 1/2 Yellow Non-yellow F generation Yellow Yellow Non-yellow Dead

# 1 b) An allele for coat color in mice, Y, produces a yellow coat color when present. The phenotypes of the F1 generation are shown. A cross between a Non-yellow mouse and yellow mouse produces half yellow and half non-yellow progeny (offsprings). Non-yellow happens to be white in this example, but it does not need to be; it can be black, grey, or some other mouse color. How does the F1 generation ratio differ from the expected mendelian ratios for a heterozygous, hybrid cross? * generation Yellow Non-yellow Yellow Yellow Gametes Meiosis Fertilization 1/2 1/2 Yellow Non-yellow F generation Yellow Yellow Non-yellow Dead

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter5: The Inheritance Of Complex Traits

Section: Chapter Questions

Problem 5QP: As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women....

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In dogs, dark coat color is dominant over albino, andshort hair is dominant over long hair. Assume that theseeffects are caused by two independently assorting genes.Seven crosses were done as shown below, in which D andA stand for the dark and albino phenotypes, respectively,and S and L stand for the short-hair and long-hairphenotypes.Number of progenyParental phenotypes D, S D, L A, S A, La. D, S × D, S 88 31 29 12b. D, S × D, L 19 18 0 0c. D, S × A, S 21 0 20 0d. A, S × A, S 0 0 29 9e. D, L × D, L 0 31 0 11f. D, S × D, S 45 16 0 0g. D, S × D, L 31 30 10 10Write the genotypes of the parents in each cross. Use thesymbols C and c for the dark and albino coat-color allelesand the symbols H and h for the short-hair and long-hairalleles, respectively. Assume parents are homozygousunless there is evidence otherwise.
In chickens, the Leghorn variety has white feathers due to an autosomal dominant allele. Silkies have white feathers due to a recessive allele in a second (different) gene. If a true-breeding whiteLeghorn is crossed to a true-breeding white Silkie, what is theexpected phenotype of the F1 generation? If members of the F1generation are mated to each other, what is the expected phenotypic ratio of the F2 generation? Assume the chickens in the parental generation are homozygous for the white allele at one gene andhomozygous for the brown allele at the other gene. In subsequentgenerations, nonwhite birds will be brown.
In the clover butterfly, males are always yellow, but females can beyellow or white. In females, white is a dominant allele. Two yellow butterflies were crossed to yield an F1 generation consisting of50% yellow males, 25% yellow females, and 25% white females.Describe how this trait is inherited and specify the genotypes ofthe yellow parents.
What is a reciprocal cross? Suppose that a gene is found as a wildtype (functional) allele and a recessive mutant (nonfunctional)allele. What would be the expected outcomes of reciprocal crossesif a true-breeding normal individual was crossed to a true-breedingindividual carrying the mutant allele? What would be the results ifthe gene is maternally inherited?
Skin color in humans is determined by polygenic inheritance, which means the more dominant alleles there are, the darker the skin color will be. A medium-toned skinned woman (AaBb) has a child with another medium-toned skinned man (AaBb). What is the probability of them having a very dark-toned skinned child? (Hint: the genotype is homozygous dominant)
In humans, the ABO blood type is under the control of autosomalmultiple alleles. Red–green color blindness is a recessiveX-linked trait. If two parents who are both type A and have normalvision produce a son who is color-blind and type O, what isthe probability that their next child will be a female who has normalvision and is type O?
Two genes control color in corn snakes as follows:O– B– snakes are brown, O– bb are orange, oo B– areblack, and oo bb are albino. An orange snake wasmated to a black snake, and a large number of F1progeny were obtained, all of which were brown.When the F1 snakes were mated to one another, theyproduced 100 brown offspring, 25 orange, 22 black,and 13 albino.a. What are the genotypes of the F1 snakes?b. What proportions of the different colors wouldhave been expected among the F2 snakes if the twoloci assort independently?
In rabbits, black hair is due to a dominant allele B and brown hair to its recessive allele b. Short hair (H) is dominant to long hair (h). In a cross between a homozygous black, longhaired rabbit and a brown, homozygous shorthaired one, what would the F1 generation look like? If you did not know the genotype of an F1 rabbit, you could determine its genotype by a test cross in which it is crossed with an animal with which phenotype AND genotype If you carried out this test cross, what phenotypes and in what ratio would you expect? What phenotypes in what ratio would be expected in the F2 generation?
In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?
In humans, a very rare dominant allele that causes the little fingerto be crooked has a penetrance of 80%. In other words, 80% of heterozygotes carrying the allele will have a crooked little finger. If ahomozygous unaffected person has children with a heterozygotecarrying this mutant allele, what is the probability that an offspring will have a little finger that is crooked?
In rabbits, the coat color black dominant (B) over brown (b). Short hair is dominant (S) over long (s). In a cross between a homozygous black short-haired male and a brown homozygous long-haired female, what would be the ratios for genotype and phenotype of the F1 generation?
In rabbits, black hair is due to a dominant allele B and brown hair to its recessive allele b. Short hair (H) is dominant to long hair (h). Show punnet squares In a cross between a homozygous black, longhaired rabbit and a brown, homozygous shorthaired one, what would the F1 generation look like? If you did not know the genotype of an F1 rabbit, you could determine its genotype by a test cross in which it is crossed with an animal with which phenotype AND genotype? If you carried out this test cross (from 2, using the F1 from 1), what phenotypes and in what ratio would you expect? What phenotypes in what ratio would be expected in the F2 generation of the cross in point 1?