1- Evaluate the following postfix expressions and write out a corresponding infix expression: 2324* +* 12-32^3* 6/+ 1234 ^*+ 25^1- 2 Convert the following equations from infix to postfix: 2^3^3+5*1 233^^51*+ 11 +2-1*3/3 + 2^2/3 11 +13*3/-22^3/+ 3- Evaluation using stack 1-2^3^3-(4+5*6*7) * 8 Show algorithm in action on above equation 4- Expressions, programs, etc can be represented by tree structures E.g. Arithmetic Expression Tree A-(C/5 * 2+7) + (D*5 % 4) 5-Draw the binary search tree that would result from the insertion of the following integer keys: 14 58 18 10 99 52 33 69 74 17

1- Evaluate the following postfix expressions and write out a corresponding infix expression: 2324* +* 12-32^3* 6/+ 1234 ^+ 25^1- 2 Convert the following equations from infix to postfix: 2^3^3+51 233^^51+ 11 +2-13/3 + 2^2/3 11 +133/-22^3/+ 3- Evaluation using stack 1-2^3^3-(4+567) 8 Show algorithm in action on above equation 4- Expressions, programs, etc can be represented by tree structures E.g. Arithmetic Expression Tree A-(C/5 * 2+7) + (D*5 % 4) 5-Draw the binary search tree that would result from the insertion of the following integer keys: 14 58 18 10 99 52 33 69 74 17

Name: i need the answer quickly 1- Evaluate the following postfix expression
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: i need the answer quickly 1- Evaluate the following postfix expressions and write out acorresponding infix expression:2324*+*12-32^3* 6/+1234 A*+25^1-2 Convert the following equations from infix to postfix:2^3^ 3 + 5 * 1233A^51 * +11 + 2-1*3/3+2^2/31

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

A set of eight data bytes is stored in memory locations starting from XX70H. Write a program to add two bytes at a time and store the sum in the same memory locations, low order sum replacing the first byte and a carry replacing the second byte. If any pair does not generate a carry, the memory location of the second byte should be cleared. Data(H) F9, 38, A7, 56,98,52, 8F, F2
Consider the following two operations: (a) PC = PC + 4; (b) PC = PC + offset (offset is a positive or negative multiple of 4).Which of the following statements is true? a In the MIPS architecture, operation (b) is done by performing operation (a) as many times as required. b Operation (a) requires about 1/2 as much hardware to implement as does operation (b) c Operation (a) is simply done by replacing the right-most two bits of PC with 00. d Since (a) is a special case of (b), these two operations require the same hardware to implement.
25: . Find the time delay in the following program if the crystal frequency is 1 MHz. Do not ignore the time delay due to the first and last instruction. DELAY: LDI R16, 30 AGAIN: LDI R17, 35 HERE: NOP NOP DEC R17 BRNE HERE DEC R16 BRNE AGAIN RET 26: Write a program to display 2 on 7 segment. A 7 segment is connected to PortD.
Q3. IF PC = 682 AR=123,DR=A2BF , IR = 567 , then execute the following M[AR] <-- DR IRM <-- [AR] Determine the value of IR after the execution and comment on the type of addressing.
CD sub Define the terms quadruple, triple and indirect triples. Give their representation for the assignment statement A=B * (C-D) by generating an appropriate three address code.
The following C code is a formula representing the Volume of a Circular Cone. Convert into MIPS code. (You don’t need to convert to machine code.) Assume that the variables volume, radius, and height are mapped into the floating point registers $f0 , $f1, and $f2 respectively. Volume = (3.14) * pow(radius,2) * height / 3.0
MIPS Assembly: Below is the code and attached is the syntax error it has. Please fix the syntax error and print the output. Attached is image of what the output must be. Data.asm .dataarr: .word 7, 9, 4, 3, 8, 1, 6, 2, 5n: .word 9 n .text.globl mainmain:la $t0, arr # Load address of arrla $t1, n # Load address of nlw $t2, 0($t1) # Load n into $t2 jal radixSort # Call radixSort la $a0, arr # Load address of arrlw $a1, 0($t1) # Load n into $a1jal printData # Call printData li $v0, 10 # Exit the programsyscallradixSort:la $a0, arr # Load address of arrlw $a1, 0($t1) # Load n into $a1 jal getMax # Call getMax move $t3, $v0 # Move the max to $t3move $t4, $zero # Move 0 to $t4 loop:ble $t3, $zero, Exit # Check if m/exp <= 0 mul $t5, $t4, 10 # Multiply exp by 10jal countSort # Call countSort addi $t4, $t4, 1 # Increment expdiv $t3, $t3, 10 # Divide m by 10j loop # Loop back Exit:jr $ra # ReturngetMax:move $t6, $zero # Move 0 to…
Need crt Answer else downvoted Translate the following into three address code while (A <B) do If (C<D) then X = Y + Z.
Write a MIPS program given the following data definition statements, compute the addresses of arr2, arr3, str1, and str2, given that the address of arr1 is 0x10010000. Show your steps for a full mark. Select “Show Labels Window (symbol table)” from the Settings menu in MARS to check the values of your computed addresses. .data arr1: .word 5:20 arr2: .half 7, -2, 8, -6 arr3: .space 100 str1: .asciiz "This is a message" str2: .asciiz "Another important string"
Modify the following program in lc-3 to get the input(numbers) from the keyboard and print the result to console. .ORIG x3000Loop LD R0, number1 ; load number1 into R0LDR R1, number2 ; load number2 into R1ST R2, SaveR2 ; save register R2LD R5, goSUB ; load address of SUB into R4JSRR R5 ; go to subroutine whose address in R5STR R3, result ; store resultLD R2, SaveR2 ; restore old value R2HALTnumber1 .FILL #10number2 .FILL # -8goSUB .FILL SUB ; initialize goSUB to address of SUBSaveR2 .BLKW #1; reserve space SaveR2 and SaveR3result .BLKW #1SUB NOT R1, R1ADD R2, R1, #1ADD R3, R0, R2RET.END
Which of the following segments of C code best describes what the following MIPS assembly code does? la $t0, x lw $t1, 0($t0) la $t2, y lw $t3, 0($t2) li $t4, 42 l1: bne $t4, $t1, l2 addu $t1, $t1, $t3 l2: sw $t1, 0($t0) Group of answer choices a) while (x==42) { x=x+y; } b) if (x==42) { x=x+y; } c) while (x!=42) { x=x+y; } d) if (x!=42) { x=x+y; } e) x=x+y;
In the following code, the first printf() reached produces the output “14,” but the second printf() can cause a bus error or a segmentation fault. Why? main(){ int *p;funct(p);printf("%d\n",*p);}funct(int *p2){p2=(int *)malloc(4);*p2=14;printf("%d\n",*p2);}