1 Find that antiderivative of the function whose value at X = –1 is x2 + 4x + 5 0. x + 1 In |x+5 - In 2 IT tan-' (x + 2) – 4 - None of these IT 2 tan- (x + 2) + 4 x + 2 It tan - 4 +

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Q: #35

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