  V4+/3x14. f(x)=/12 +15. f(x)sin16. f(x)= tan xx 2fx) = 4 cos5x.f(x) = cos2 ( 318. f(x)= 4x + 5tan (x420. f(x)01 121. f(x)= 2 sec2 (x)322. f(x)=COSabr24. f(x) V3x23. f(x)=Vcos (5x)25. f(x) = [x +csc (x+3)]26. f(x) [xsec (4x 2)]4O nie +227-40 Find dy/dx.27. y x sin2 (5x)28. y Vx tarXsi30. y=.529. y x sec (1/x)sec (3032. y sin (t31. y cos (cos x)1 +34. y 1-333. y = cos (sin 2x)636. у 3 (х*36. y= (x(5x + 8)' (1 - Vx35. y1x-51338. y37. у —2x+1(2x+ 3)339. y4x2 1)40. y [1 -

Question

#35 help_outlineImage TranscriptioncloseV4+/3x 14. f(x)=/12 + 15. f(x) sin 16. f(x)= tan x x 2 fx) = 4 cos5x .f(x) = cos2 ( 3 18. f(x)= 4x + 5 tan (x 4 20. f(x) 01 1 21. f(x) = 2 sec2 (x) 3 22. f(x) =COS abr 24. f(x) V3x 23. f(x)= Vcos (5x) 25. f(x) = [x +csc (x+3)] 26. f(x) [x sec (4x 2)]4 O nie + 2 27-40 Find dy/dx. 27. y x sin2 (5x) 28. y Vx tar X si 30. y= .5 29. y x sec (1/x) sec (3 032. y sin (t 31. y cos (cos x) 1 + 34. y 1- 3 33. y = cos (sin 2x) 6 36. у 3 (х* 36. y= (x (5x + 8)' (1 - Vx 35. y 1 x-513 38. y 37. у — 2x+1 (2x+ 3)3 39. y4x2 1) 40. y [1 - fullscreen
Step 1

35) to differentiate the given function

Step 2 help_outlineImage Transcriptionclosey=f(x)=g(x)h(), where g(a)= (5x+8)',h(x)= (1-x) Apply product rule: y'f(x)= g'(ax)M{t)+g(»)h(cx) fullscreen
Step 3

Apply chain rule to differe... help_outlineImage Transcriptioncloseg(x)= (5x + 8),h) (1-x) g(x) 7(5r+8).5 35(5x +8) hc) = 6(-r}(-}}=30-a 2Vx Vx fullscreen

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