1) Given the map a15b24c (where 15 and 24 are the respective map distance between the loci) with a coefficient of coincidence of 0.5, how many "abc" pheontype individuals would be observed among 1000 progeny of a test cross of the following: a+c/+b+

1) Given the map a15b24c (where 15 and 24 are the respective map distance between the loci) with a coefficient of coincidence of 0.5, how many "abc" pheontype individuals would be observed among 1000 progeny of a test cross of the following: a+c/+b+

Name: 1) Given the map a15b24c (where 15 and 24 are the respective map dista
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Description: 1) Given the map a15b24c (where 15 and 24 are the respective map distance between the loci) with a coefficient of coincidence of 0.5, how many "abc" pheontype individuals would be observed among 1000 progeny of a test cross of the following: a+c/+b+2

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter11: The Basic Principles Of Heredity

Section: Chapter Questions

Problem 11TYU: Individuals of genotype AaBb were mated to individuals of genotype aabb. One thousand offspring were...

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A series of three-point testcrosses is made to determine the genetic map order of seven linked allele pairs: A/a, B/b, G/g, H/h, Q/q, R/r, and Y/y.From each cross between a triply heterozygous parent listed below, two recombinant classes were noticed as the least frequent among all 8 progeny classes, and are listed at the right in the table. A. For each testcross write the genotype of the F1 heterozygous parent. F1 Parental Phenotype Least frequent F2 Phenotype 1.AHB&ahb AHb & ahB 2.RYh&ryH RYH & ryh 3.BhY&bHy Bhy & bHY 4.qYB&Qyb qYb & QyB 5.AbQ&aBq Abq & aBQ 6.ghR&GHr ghr & GHR B. Write the unified map order of these genes, showing your reasoning.
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