These are bitwise operations using C syntax Problem 2 (Bitwise)Bookmark this pageWhich number?1) Here is a numerical expression in C: x << 1 containing an unknown number x. If the value of the whole expression( x << 1 ) is 42, what is the value of x?2) Here are a couple of numerical expressions in C: x % 5 and x 5 containing an unknown number x. If the value of theexpression first expression is 4 and the value of the second is 3, what is the value of x?3) Here are a couple of numerical expression in C: x & 25value of the second is 29, what is the numerical value of this expression?and x | 25 . If the value of the first expression is 17 and theLay out the bit patterns of 25, 17 and 29. Consider the bitwise OR first: this will fix all but three of the bits of x. Considering thebitwise AND will fix the remaining three.Save Reset

The solution is an given below :

Answered: 1) Here is a numerical expression in C:…

1) Here is a numerical expression in C: x << 1 containing an unknown number x. If the value of the whole expression x << 1 ) is 42, what is the value of x?

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter2: Problem Solving Using C++using

Section2.6: A Case Study: Radar Speed Traps

Problem 3E

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Question

These are bitwise operations using C syntax

Problem 2 (Bitwise)
Bookmark this page
Which number?
1) Here is a numerical expression in C: x << 1 containing an unknown number x. If the value of the whole expression
( x << 1 ) is 42, what is the value of x?
2) Here are a couple of numerical expressions in C: x % 5 and x 5 containing an unknown number x. If the value of the
expression first expression is 4 and the value of the second is 3, what is the value of x?
3) Here are a couple of numerical expression in C: x & 25
value of the second is 29, what is the numerical value of this expression?
and x | 25 . If the value of the first expression is 17 and the
Lay out the bit patterns of 25, 17 and 29. Consider the bitwise OR first: this will fix all but three of the bits of x. Considering the
bitwise AND will fix the remaining three.
Save Reset

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