1 LetXbeadiscreterandom variablewithprobabilityfunctionp(x), g1(X),g2(X),g3(X),···,gk(X) be k functions of X. Then E[g1(X)+g2(X)+g3(X)+···+gk(X)] ≡ E[g1(X)]+E[g2(X)] +···+E[gk(X)] Proof for the case of k = 2
1 LetXbeadiscreterandom variablewithprobabilityfunctionp(x), g1(X),g2(X),g3(X),···,gk(X) be k functions of X. Then E[g1(X)+g2(X)+g3(X)+···+gk(X)] ≡ E[g1(X)]+E[g2(X)] +···+E[gk(X)] Proof for the case of k = 2
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter3: Groups
Section3.2: Properties Of Group Elements
Problem 31E: 31. Prove statement of Theorem : for all integers and .
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LetXbeadiscreterandom variablewithprobabilityfunctionp(x), g1(X),g2(X),g3(X),···,gk(X) be k
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