last two plz (1 point) Approximate cos(4.6) using a quadratic approximation:First note that cos(4.6) cos(3/2).Let f(x) = cos(x). Then,f'(x) = -sinxandf"(x) = -cosxLet a = 3π/2. Thenf' (3/2) = -sin(3pi/2)andf" (31/2) = -cos(3pi/2)Q(x), the quadratic approximation to cos(x) at a = 3π/2 is:Q(x) =Use Q(x) to approximate cos(4.6)cos(4.6)

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(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f'(3/2) = -sin(3pi/2) and f" (31/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) =| Use Q(x) to approximate cos(4.6). cos(4.6)

(1 point) Approximate cos(4.6) using a quadratic approximation: First note that cos(4.6) cos(3/2). Let f(x) = cos(x). Then, f'(x) = -sinx and f"(x) = -cosx Let a = 3x/2. Then f'(3/2) = -sin(3pi/2) and f" (31/2) = -cos(3pi/2) Q(x), the quadratic approximation to cos(x) at a = 3/2 is: Q(x) =| Use Q(x) to approximate cos(4.6). cos(4.6)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter6: The Trigonometric Functions

Section6.4: Values Of The Trigonometric Functions

Problem 23E

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