(1) Solve the following: (a) 42x-1 = 64 (b) 81–x = 4×+2 (© 22x + 2* = 12 = 0 (d) In 3 – In x – In(x+ 5) = 0 (e) log4(x + 2) = log,(x – 1) = 1 O log2 (x – 1) – log2(x + 3) = log2 (2) The price of a dress is reduced by 20%, When the dress still does not sell, price was then reduced by 1

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 14EQ
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Problem Set: B
(1) Solve the following:
(a) 42x-1 = 64
(b) 81–* = 4x+2
(©) 22* + 2* = 12 = 0
(d) In 3 – In x – In(x + 5) = 0
(e) log,(x + 2) – log4(x – 1) = 1
() log, (x – 1) – log, (x + 3) = log2
(2) The price of a dress is reduced by 20%. When the dress still does not sell, price was then reduced by 10%
of the reduced price. If the price of the dress after both reductions is $264, what was the original price?
(3) If a projectile is launched into the air at 29.4 feet per second from a height of 60 feet,
its height (in feet) is given by S(x) = 60 + 29.4x – 9.8x?, where x is in seconds.
Showing all working, determine:
(a) How long will it take the projectile reach its maximum height?
(b) What is the highest height that the projectile can attain?
Transcribed Image Text:3 of 9 + Automatic Zoom >> Problem Set: B (1) Solve the following: (a) 42x-1 = 64 (b) 81–* = 4x+2 (©) 22* + 2* = 12 = 0 (d) In 3 – In x – In(x + 5) = 0 (e) log,(x + 2) – log4(x – 1) = 1 () log, (x – 1) – log, (x + 3) = log2 (2) The price of a dress is reduced by 20%. When the dress still does not sell, price was then reduced by 10% of the reduced price. If the price of the dress after both reductions is $264, what was the original price? (3) If a projectile is launched into the air at 29.4 feet per second from a height of 60 feet, its height (in feet) is given by S(x) = 60 + 29.4x – 9.8x?, where x is in seconds. Showing all working, determine: (a) How long will it take the projectile reach its maximum height? (b) What is the highest height that the projectile can attain?
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