1- Tension force of BC (TBC) is dependent on tension force of AB (TAB) by  ?  2- The tension force of AB (TAB) is related to w by ?  3- The tension force of BC (TBC) is related to w by ?    4- The allowable stress (σ all.) is ?    5- The maximum safe value of w is ?

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1- Tension force of BC (TBC) is dependent on tension force of AB (TAB) by  ? 

2- The tension force of AB (TAB) is related to w by ? 

3- The tension force of BC (TBC) is related to w by ? 
 
4- The allowable stress (σ all.) is ? 
 
5- The maximum safe value of w is ? 
 
 
 
 
Expert Solution
Part-1 Step-1

Given:

Dimensions as given in figure.

Advanced Physics homework question answer, step 1, image 1

Step 2

The equation for triangle AEB can be given by,

tanθ1=AEEBθ1=tan-112θ1=26.56o

The equation for triangle BDC can be given by,

tanθ2=CDDBθ2=tan-166θ2=45o

Step 3

Now resolving the tensions TAB and TBC in vertical and horizontal directions.Advanced Physics homework question answer, step 3, image 1

 

 

Step 4

The equation for net horizontal forces can be given by,

Fx=0TBCsinθ2-TABsinθ1=0TBCsinθ2=TABsinθ1

 

Substitute 45o for θ2 and 26.56o for θ1 to obtain the relation between tensions.

TBCsin45o=TABsin26.56oTBC=TABsin26.56osin45o

             TBC=0.632TAB...... (1)

Therefore, tension force of BC (TBC) is dependent on tension force of AB (TAB) by (0.632)TAB.

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