1-The following program is supposed to add the contents of memory location 8000 h to the Accumulator .The program works correctly only part of the time .Show that is wrong with the program and how to correct it. MOV B, A LDA 8000 ADC B HLT
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- For the following code, explain what the register file and forwarding unit are doing during thefifth cycle of execution. If any comparisons are being made, mention them. Remember, usethe forwarding unit from class, not the book. LOOP:LDUR X1, [X6, #40]ADD X5, X5, X8ADD X6, X6, X8STUR X1, [X5, #20]CBZ X1, LOOPPlease indicate whether this following statements are true or false and WHY? The MIPS load instruction needs to access memory once. If a branch is taken, the PC will be set to the next sequential instruction. To optimize performance in general, we should first focus on the rare cases.Variable A contains the value 0x01. What will be the content of the Z status bit after execution of the following instruction? movf A, W Z = [?]
- 80/20 rule states that 80% of the instruction ios executed and 20% of the instruction is generated is it true?a) How does MIPS know where to fetch the next instruction from the main memory? In which segment ofmemory should this instruction exist?b) Why is the data segment after the text segment in the main memory?c) How many bytes would you need to allocate to store an array with 20 integers using the conventionused throughout the semesterPlease convert the following segment of code into LEGv8/ARMv8. Assume g and h are in registers X19 and X20 respectively and explain line by line. if (g < h): g=g+ h; else: h = h * 2
- 1. The hypothetical machine has two I/O instructions: 0011 = Load AC from I/O 0111 = Store AC to I/O In these cases, the 12-bit address identifies a particular I/O device. List the steps for every execution for the following program and illustrate using table that explain the process below : a. Load AC from device 5. b. Add contents of memory location 940. c. Store AC to device 6. d. Assume that the next value retrieved from device 5 is 3 and that location 940 contains a value of 2. Please pointing a, b,c ans. Because one I already upload this question and I didn't understand which one is and of a...please write ans a, b , c please14--> ) According to the memory view given below. If RO = 0x20000004, after the LDMIA rO, (r7, r3, r9} instruction is executed, which of the following is the r3 and r0 register contents, respectively (data layout to.g endian)?1- Repeat the previous example using memory- mapped I/O technique?
- [Note: You are allowed to use only instructions implemented by the actual MIPS hardwareprovided in attached photos below. Use assembly language format from the references orthe book. Note, base ten numbers are listed as normal (e.g. 23), binary numbers areprefixed with 0b and hexadecimal numbers are prefixed with 0x.] Write a C program and corresponding assembly program based on MIPS ISA that reads three edges for a triangle and computes the perimeter if the input is valid. Otherwise, display that the input is invalid. The input is valid if the sum of every pair of two edges is greater than the remaining edge. [Direction: You can consult any resources such as books, online references, and videosfor this assignment, however, you have to properly cite and paraphrase your answerswhen it is necessary.] solve it any how urgently please.Q3/ write a program to cout number of one's & zero's in a number stored at 0200:0010, use rotate instruction, store the result in the memory location 0200:0011 and 0200:0012 respectively.What will be the contents of AX, BX, CX and DX registers after the execution of the following program? MOV DX, 1234 MOV CL, 0F MOV BH, AB MOV AX, 6589 ADD DX, AX MOV AH, 12 Lab1: OR AH, CL MOV DL, 41 MOV BX, F0 MOV CL, 3A LOOP Lab1 INC BX SHR BX,2