The super-container vessel in the figure has a total mass displacement of (54*1000) long tons. This vessel towed by a tugboat with α=20⁰ angle with horizontal. If a constant tension is applied as F=45*10 kN by the tugboat, please calculate the time to bring the vessel to a speed of 2 knot from the rest. At these low speeds, please neglect the hull resistance that created by the motion. Note: (1 long tons = 1016.05 kg, 1 knot=1.151 mi/hr= 0.5144 m/s) 1-The super-container vessel in the figure has a total mass displacement of(54*1000) long tons. This vessel towed by a tugboat with a=20° angle withhorizontal. If a constant tension is applied as F=45*10 kN by the tugboat, pleasecalculate the time to bring the vessel to a speed of 2 knot from the rest. At theselow speeds, please neglect the hull resistance that created by the motion.Note: (1 long tons = 1016.05 kg, 1 knot=1.151 mi/hr= 0.5144 m/s)CNA CEN

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Chapter5: Newton's Laws Of Motion

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The super-container vessel in the figure has a total mass displacement of (54*1000) long tons. This vessel towed by a tugboat with α=20⁰ angle with horizontal. If a constant tension is applied as F=45*10 kN by the tugboat, please calculate the time to bring the vessel to a speed of 2 knot from the rest. At these low speeds, please neglect the hull resistance that created by the motion.

Note: (1 long tons = 1016.05 kg, 1 knot=1.151 mi/hr= 0.5144 m/s)

1-
The super-container vessel in the figure has a total mass displacement of
(54*1000) long tons. This vessel towed by a tugboat with a=20° angle with
horizontal. If a constant tension is applied as F=45*10 kN by the tugboat, please
calculate the time to bring the vessel to a speed of 2 knot from the rest. At these
low speeds, please neglect the hull resistance that created by the motion.
Note: (1 long tons = 1016.05 kg, 1 knot=1.151 mi/hr= 0.5144 m/s)
CNA CEN

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