1: unsigned int n1,result; _asm { 2: mov eax, n1 3: mov edx, 20 4: add eax, edx 5: mov result,eax } Line 2 addressing mode is Select one: a. Immediate b. Register c. Memory
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A: Introduction
1: unsigned int n1,result;
_asm
{
2: mov eax, n1
3: mov edx, 20
4: add eax, edx
5: mov result,eax
}
Line 2 addressing mode is
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- A(n) __________ is a storage location implemented in the CPU.Most Intel CPUs use the __________, in which each memory address is represented by two integers.Select all true statements. Segmentation always uses 32-bit logical addresses. The memory management unit utilizes the segment component of the logical address to get the segment table start address and adds the offset to obtain the physical address. Segmentation uses segment and offset logical addresses. Maximum segment number limits segment length. Segmentation restricts process memory access to respective segments. Segments may be granted privileges.
- (True/False): The PTR operator returns a variable's 32-bit address.switch (c) { case 1: a = 10; break; case 2: a = 20; break; case 3: a = 30; break; default: a = 0; } Translate this piece of C codes into ILOC codes. Variable c and a should be stored in the activation record. Your translated codes start at address 1000 and grow to larger addresses. The address of a variable in the activation record is r_arp[@name], where r_arp is the register storing the activation record address and @name is the macro for the offset of the variable name. You may use labels instead of address number in jump/branch instructions.[ Direction: Any how solve the question please. Don't reject the question. if you need 2 /3 hours to solve the question please take it but don't reject the question. solve it properly,correctly.You can consult any resources such as books, online references, and videos for this assignment, however, you have to properly cite and paraphrase your answers when it is necessary. ] The following figure represents both datapath and controlpath for MIPS architecture that implements most of the fundamental instrucons.
- IN asmly language please Pretty please with successful build screen shot and output 1.Using the AddTwo program from Section 3.2 as a reference, write a program that calculates the following expression, using registers: A = (A + B) − (C + D). Assign integer values to the EAX, EBX, ECX, and EDX registers. Note: you can hard code integer literal onto the registers, e.g. mov eax,55 ; AddTwo.asm - adds two 32-bit integers.; Chapter 3 example .386.model flat,stdcall.stack 4096ExitProcess proto,dwExitCode:dword .codemain proc mov eax,5 add eax,6 invoke ExitProcess,0main endpend main 2. Listing File for AddTwoSum Generate a listing file for AddTwoSum.asm(in 3.4.3 of the text) and write a description of the machine code bytes generated for each instruction. You can write your descriptions directly over the .lst file. You might have to guess at some of the meanings of the byte values. Submit the .lst file with your description over it.…86. Division by zero error are caused by a. user defined code b. OS code c. process d. interruptbyte sayi1=0xF0;byte sayi2 = 0xAB;byte temp;temp = (byte)(sayi1 | sayi2);Console.Write(temp + "");temp = (byte)(sayi1 ^ sayi2);Console.WriteLine(temp); what will be the screen output of this code
- __ is a constant (numeric value) or an address that determines the upper limit of the test range.0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.CODE (EMU8086) #START = THERMOMETER.EXE##START = LED_DISPLAY.EXE#.STACK 100H .MODEL SMALL .DATA MSG1 DB 10,13,' WELCOME ', DB 10,13,' CHOOSE TYPE OF FOOD ', DB 10,13,'1.) PIZZA 2.) BAKED MACARONI 3.) FRENCH FRIES', DB 10,13,'ENTER: $' MSG2 DB 10,13,'PLEASE SELECT WHAT WILL BE THE MAX TEMPERATURE', DB 10,13,'1.) 20 DEG', DB 10,13,'2.) 40 DEG', DB 10,13,'3.) 60 DEG', DB 10,13,'4.) 80 DEG', DB 10,13,'5.) 100 DEG', DB 10,13,'6.) 119 DEG', DB 10,13,'ENTER: $' NUM1 DB 20 NUM2 DB 40NUM3 DB 60NUM4 DB 80NUM5 DB 100NUM6 DB 119 TIMEOP1 DB 10,13,'SET THE TIMER', DB 10,13,'ENTER 1: 00:00:50', DB 10,13,'ENTER 2: 00:01:40', DB 10,13,'ENTER 3: 00:02:30', DB 10,13,'ENTER 4: 00:03:20', DB 10,13,'ENTER 5: 00:04:10', DB 10,13,'ENTER: $' A DB 0B DB 0C DB 0D DB 0 OPTIONERROR DB 10,13,'INVALID OPTION $' DONE DB 'DONE','$' RESTARTMENU1 DB 10,13,'PRESS 1 TO GO BACK TO…
