'1+ we For a given soil, show that: Ysat = n( We n() Yo Soil Mechanics
Q: A saturated soil sample (S=100%) contains 28 g of soil solids and 22 g of water. The void ratio is…
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Q: For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the dry density of soil in slug/ft3. Note p…
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Q: soil sample has avoid ratio of 0.72, moisture content = 15% and Gs=2.72 determine the following:…
A: Given data : Void ratio=ee=0.72Moisture content=w%w%=15Specific gravity=GSGS=2.72To find :Dry unit…
Q: A 0.4-m3 moist soil sample has the following: • Moist mass = 711.2 kg • Dry mass = 623.9 kg •…
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Q: The moist unit weight of a soil is 16.5 kN/m'. Given that the w = 15% and G, = 270, find: (1) Dry…
A: Using formula to dry unit weight
Q: Given data Degree of saturation=D0.5 Void ratio=0:47 Specific gravity of soil=2.7 Determine water…
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Q: A compacted sample of soil with a bulk unit weight of 1300 kg/m has a water content of 40%. Assume…
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Q: sample. The hydraulic cConductivities of the soils in the direction of flow through them are as…
A: Darcy's law is an equation that describes the flow of a fluid through a porous medium. V = K i…
Q: 3.18 The moist unit weights and degrees of saturation of a soil are given in the table. y (lb/ft°) S…
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Q: For the soil profile shown in Figure, u 5 points at point B= -22.5 kN/m2, The value of Z and ov' at…
A: unit weight γsand=G+Se1+eγw S=1 saturated and unit wt of water γw=9.81…
Q: 15. The following are results of a field unit weight determination test using sand cone method:…
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Q: The Poisson's ratio for soil sample 1 and 2 are µj and µ2 1-41 = 1.5 and 1-42 respectively. If…
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Q: Q. No 1. Solve the following example for D10, D30, D60, coefficient of curvature and coefficient of…
A: Sieve Mass % mass Cumulative % % No Sieve size Retained Retained Retained Finer…
Q: Question 27 1 points Save Ansv For a given soil, the following are given: Gs = 2.63; moist unit…
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Q: The moist unit weights and degrees of saturation of soil are given in the table
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Q: Water flows through a sand filter as shown on the figure. The soil has a cross sectional area of…
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Q: A soil has a saturated unit weight of 19.8 kN/m³. If w = 45%, what is the dry unit weight in lb/yd³?…
A: Given:saturated unit weightγsat=19.8 KN/m3moisture content(w)=45%w=0.45Degree of…
Q: Layer no. Thickness (m) Soil parameters H, = 4 H. = 5 H; = 3 e = 0.4, G, = 2.62 e = 0.60. G, = 2.68…
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Q: e figure below shows layers of soil in a tube that is 100 mm x 100 mm in cross section. Water is…
A: Given data in question Flow length of different soils Permeability of each soil Cross sectional…
Q: The Poisson's ratio for soil sample 1 and 2 are µj and µ2 respectively. 1-41 1-42 If H2 1.5 and…
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Q: adjacent figure Soil 1 G, = 2.0 2 m e=0.55 不 2 m Soil 2 G, = 2.9 e= 0.48 w= 34.65% Soil 3 3 m G,=…
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Q: For a soil if Poisson's ratioµ = 0.333, the coefficient of earth pressure at rest will be (a) 0.5…
A: Given data : Poisson's ratio (μ)=0.333
Q: For a given soil, show that e n = 1+e
A: Derivations can be done in many ways one of such kind is shown below:
Q: Given data: Weight of dry soil=40 KN Volume of soil=2.36 m3 Find dry unit weight
A: The given question is related with geotechnical engineering . The given question contain value of…
Q: For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the moist unit weight of soil in KN/m3.…
A: Soil sample given-Void ratio e=0.75water content w=22%=0.22G=2.66
Q: The layer of soil shown has the corresponding coef. of permeability. It is required to compute the…
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Q: The total volume of a soil specimen is 80,000 mm3 and it weighs 150 grams. The dry weight of the…
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Q: Water flows through a sand filter as shown on the figure. The soil has a cross sectional area of…
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Q: 54. Radus, A soil sample has an average grain diameter as 0.03 mm. The size of interstices is one…
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Q: Water flows through a sand filter as shown on the figure. The soil has a cross sectional area of…
A: Discharge through soil is given by Q = KiA K is equivalent permeability i is hydraulic gradient A…
Q: The moist unit weights and degrees of saturation of a soil are given below degree of saturation…
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Q: Moisture content of a soil can be expressed as .... اختر واحدة أو أكثر a. all of these b. time c.…
A: moisture content can be expressed as wet weight
Q: Thäi 11 given a natural soil sample with (e=0.7 10= -Ul &K, , S=80% , GS=2.7 Kn/m3).compute 1. dry…
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Q: Situation 2 A soil sample in its natural state, when fully a water content 36.2%. Assume Gs = 2.69.…
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Q: The Following results were obtained From a standard Compaction test on a Soil: Soil Mechanics The…
A: Given specific gravity of soil G = 2.7 Plot dry density vs water content Water content corresponding…
Q: Total Weight of Retained Mass Sand Weight of Soil Sample (kg) 1.39 Location Moisture of Sand Content…
A: A Contractor requested concrete pouring as part of an ongoing land development project. The…
Q: Soil Mechanics (1) For a soil, the following are given: Specific gravity = 2.67, moist unit weight =…
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Q: Atterberg's Ilimits Problem 4.3 Results from liquid and plastic limit tests conducted on a soil are…
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Q: Problem I: For Problem Number 30. A layered soil has the following data; H= 1.5 m H2= 2.5 m k =…
A: Hello dear this is the solution of your problem The answer is found to be=36.80 For explanation…
Q: A sample of soil having a mass of 360 g is to be placed into a cylinder whose volume is 750 cm³. An…
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Q: Situation 1: For a given soil sample it has a specific gravity of 2.66, void ratio e=0.60is…
A: Specific Gravity = 2.66 Void ratio = 0.6 Unit weight when soil become S = 40 % Ysat = [(…
Q: Situation 10: A soil sample has water content of 25%, degree of saturation of 80%, and specifie…
A: Introduction- The amount of water contained in a substance, such as soil (called soil moisture),…
Q: For a soil, given e= 0.75, w= 22%, Gs= 2.66, calculate the moist unit weight of soil in lb/ft3.
A: Given data Void ratio (e) = 0.75 Water containt (w) = 22% Specific gravity (Gs) = 2.66
Q: Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a…
A: Solution: Given: Soil sample mass=25g For milliequivalent/100g of soil, the value will be equal…
Q: The particle size characteristics of diameter (mm) and retained mass (g) of a soil are: For 4.75 mm…
A: Make a table as below as per given data. sieve size(mm) Retained mass (g) % weight retained…
Q: PROBLEM 4: A soil sample has a maximum dry unit weight of 125 lb/ft?. If the sample has wet unit…
A: Given data, Maximum dry density unit weight γdmax = 125 lb/ft3 Bulk unit weight γb = 135 lb/ft3…
Q: GIVEN THE FOLLOWING FOR A SOIL SAMPLE: S=0.8 n=0.28 and Gs = 2.5 FIND THE MOIST UNIT WIEIGHT. USE yw…
A: Given that..... Degree of saturation (s) = 0.8 Porosity (n) = 0.28 Specific gravity of soil ( Gs) =…
Q: The following are the results of a field density test using sand cone method. Vhole=0.0014m^3 Mass…
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Q: Calculate the Zero air void unit weight for a soil for the following moisture contents: W = 5%, W =…
A: The expression for the zero air void unit weight is given by, γzav=γww+1Gs…
Q: The dry unit weight of a soil sample is 14.8 kN/m3 Given that Gs = 2.72 and w = 17%, determine:…
A: Given:- ϒd =14.8 kN/m3 Gs=2.72 W=17%
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- The sand layer shown is 2.5m thick. Beneath the sand layer is a 1.8m thick clay layer, underneath the clay layer is a solid rock. Water table is at depth of 0.9 m below the ground surface. SAND: Ymoist= 23KN/m3 ; Ysat= 21KN/m3 CLAY: Ysat= 23 KN/m3 ; LL= 42% e=0.7 A.) Compute the overburden pressure at mid-clay layer. B.) Find the maximum surface pressure without exceeding a 139.5mm settlement in clay layer if it is assumed to be normally consolidated. C.) If surface pressure is 70kpa and pre-consolidation pressure is 80kpa, find the settlement in clay layer.Shear Strentgh of the soilA rectangular footing (4.5 x 4.36 m.) is placed 1.98 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.94 meters and followed by clay for the next 6.78 meters. The force acting on the footing is 10,700 kN. Determine the settlement of the consolidating layer in mm. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.9 kN/m3. Clay has the following properties: Unit weight = 18.3 kN/m3, Void ratio = 95, Liquid limit = 49. Round off to two decimal places.
- The soil profile at a site consists of a 2.0 m thick sand layerat the top, underlain by a 3.0 m thick clay layer. The watertable lies at a depth of 1.0 m below the ground level. Thebulk and saturated unit weights of the sand are 16.0 kN/m3and 19.0 kN/m3, respectively. The properties of the clay are:water content = 45.0%, specific gravity of the soil grains =2.70, compression index = 0.65, swelling index = 0.08, andoverconsolidation ratio = 1.5.a. The ground level is raised by placing a 1.5 m high compactedfill with unit weight of 20.0 kN/m3. What is theconsolidation settlement?b. When the consolidation due to the fill is completed,it is proposed to construct a warehouse imposing a uniform pressure of 40.0 kN/m2. What would be theconsolidation settlement due to the construction of thewarehouse?If there is a layer of sand (lower layer) under artesian pressure (causes upward flow), calculate the excavation height H so that a negative effective stress is not generated at point A and therefore the heaving of the soil at that point. Use a unit weight of water w of 62.43 lb/ft3. Note: In this example we make a similarity with the permeameter with upward flow, therefore, H1=0 since from the bottom of the excavation (Na) upwards it remains dry (pumping is done), H2= 20ft-H, h=12ft-H2.A dense silt layer has the following properties: Void ratio = 0.76, SG= 2.59. Free ground water is 9.31m below the ground. Capillary action rise will reach 7.93m. The soil above capillary action rise is dry while within the zone, it is saturated at 53.13%. Determine the effective pressure (kPa) at a depth of 7.05m from the groind surface. Use stored value. Asnwer in 5 decimal places.
- A rectangular footing (4.89 x 4.38 m.) is placed 1.21 m. below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.52 meters and followed by clay for the next 6.98 meters. The force acting on the footing is 10,293 kN. Determine the resulting stress increase at the midheight of the consolidating layer in kPa. Assume a 2V:1H pressure diagram. Unit weight of sand = 16.1 kN/m3. Unit weight of clay = 18.7 kN/m3. Use stored value. Answer in five decimal places.For a moist soil, given the following: V = 7.08 x 103 m3; W = 136.8 x 10-3 kN; W = 8%; Gs = 2.66. Determine: Dry unit weight Void ratio Volume occupied by waterA soil profile is shown in Figure 7.28. An embankment load of 500 kg/cm² is placed on the ground surface. Define the following: a. How much water will rise in the pizometer immediately after applying the load. b. What is the degree of consolidation at A if h = 26 ft. c. Determine the magnitude of h if the degree of consolidation at point A is 50%. And Draw the curve NB: part A Assume that the increase in pore water pressure is uniform over the entire depth of very clayey having a thickness of 10 ft.
- A 6 m-thick layer of stiff saturated clay is underlain by a layer of sand (Figure 8.22). The sand is under artesian pressure. Calculate the maximum depth of cut, H, that can be made in the clayThe soil profile at a site consists of 5 m sand underlain by clay layer. The ground water table is 2 m below the ground surface. Average void ratio of sand is 0.52. Water content of clay is 42% and degree of saturation of sand above water table is 37%.Assume specific gravity of sand and clay is 2.65. 1. Compute the unit weight of clay. a. 19.82 kN/m³ b. 17.47 kN/m³ c. 18.62 kN/m³ d. 16.20 kN/m³ 2. Compute the total pressure 10 m below the ground surface. a. 185.41 kPa b. 160.25 kPa c. 140.53 kPa d. 153.62 kPa 3. Compute the effective pressure 10 m below the ground surface. a. 106.94 kPa b. 96.52 kPa c. 115.62 kPa d. 108.36 kPaA rectangular footing (4.14 x 4.43 m) is placed 1.38 m below the ground surface. The soil arrangement is composed of sand (ground) for the first 6.29 m and followed by clay for the next 5.94 m. The force acting on the footing is 10581 kN. Determine the resulting stress increase at the midheight of the consolidating layer in kPa. Assume 2V:1H pressure diagram. Unit weight of sand = 16.8 kn/m3. Unit weight of clay = 18.4 kn/m3