The value of A =436, B=57, C =7 Q-4-b) The figure below shows a shunt de motor with an internal resistance of 0.25 2. It iscurrently operating with a terminal voltage of A V and an internal generated voltage Eaof (A-10) V. Calculate the armature current I4. If there is a C/5 percent decrease in flux?RA = 0.25 NRFV-A VEx=(A-10)V=KOw(1) What is the armature current Ia for EA = (A-10)V(2) What is new value of EAnew, at C/5 percent decrease in flux.(3) What is new value of Ianew, at C/5 percent decrease in flux.Answers: fill in the blanksE Anewand IAnew=

RA=0.25Ω ;VT=A=436 V ;EA1=A-10=426V ;1 IA1=? for EA=A-10 C=7, ∴C/5=7/5=1.4% decrease ∴ϕ2=0.986ϕ1 2…

(1) What is the armature current IA for EA= (A-10)V (2) What is new value of EAnew, at C/5 percent decrease in flux. (3) What is new value of IAnew, at C/5 percent decrease in flux. Answers: fill in the blanks E Anew and IAnew

(1) What is the armature current IA for EA= (A-10)V (2) What is new value of EAnew, at C/5 percent decrease in flux. (3) What is new value of IAnew, at C/5 percent decrease in flux. Answers: fill in the blanks E Anew and IAnew

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A 250 V d.c. shunt motor runs at 800 r.p.m. ,takes 12.5kW. Find resistance to be added to the field circuit to increase speed to 1000 r.p.m. at an armature current of 80 A. Assume flux proportional to field current. Armature resistance = 0.15 Ώ and field winding resistance is 250 Ώ
A 250 V, d.c. shunt motor has an armature resistance of 0.5 ohms and a field resistance of 250 ohms. When driving a load of constant torque at 600 r.p.m., the armature current is 20 A. If it is desired to raise the speed from 600 to 800 r.p.m., what resistance should be inserted in the shunt field circuit? Assume that the magnetic circuit is unsaturated
a dc shunt motor runs at 900 r.p.m from a 460 V supply when taking an armature current of 25 A. Calculate the speed at which it will run from a 230 V supy when taking an armature current of 15 A . The resistance of the armature circuit is 0.8 ohms . Assume the flux per pole at 230 V to have decreased to 75 % of its value at 460 V .
An 8 pole DC shunt generator with 900 wave-connected armature conductors supplies 10ohm at 500 V when driven at 500 rpm. The armature resistance 0.4ohm and the field resistance is 250ohm . Determine: . . 2 1.1 The flux per pole 2.1.2 The armature current for maximum efficiency if the rotational losses are 10% of the ar- mature copper losses . 3.2 A series motor runs at 600 rpm while drawing 40-A from 600-V supply. The total re- sistance of the armature and the field is 0.5-ohm. Determine the value of the additional re- sistance required in series with armature to reduce the speed to 450 rpm if the load toque is: 3.2.1 Constant 3.2.2 Proportional to the square of the speed .
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On full load a 500-volt series motor takes 100-Amp and runs at 840 rpm. The armature resistance of 0.1-ohm, field resistance 0.04-ohm. Find the speed when developing haft full load toque but with a 0.08-ohm diverter resistance parallel with the series field winding. Assume flux proportion to the field current.
A 220 V, 4 pole d.c. A shunt motor has a flux counterpole of 15 mWb and 1800 armature conductors connected in wave. Find the torque developed in newton meters and kilogram meters when the armature current is 50 A.
3-)The total Armature Winding resistance and series area winding resistance of a DC series motor are respectively; 52mΩ and 27mΩ’stop. Motor armature coefficient Ka = 40. DC series motor at 200V to feed a mechanical loadit operates and is powered by a full load current of 325A. Flux value per pole is 50mWbit is known. Brush losses are negligible. Core losses 250W and total on rotary partsmissing 60W. We will answer the following (a) What is the value of the torque produced (induced moment)? (b) calculate the speed of the engine. (c) calculate copper losses and the total loss value of the engine. (d) calculate the efficiency of the engine (Clearly write down the formulas and process stages that you use for calculations.)
A 250 V, 4 pole wave wound shunt motor has 650 conductors on itsarmature. It has armature and shunt field resistance of 0.75 ohm and 125ohms, respectively. The motor takes a current of 40 A. Estimate its speedand gross torque developed, if it has a flux per pole of 25mWb.
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Complete the wiring diagrams as per Worksheets 6-A and 6-B then solve for "A" through "K" for the DC motor on Worksheets 6-A and 6-B when it is running at capacity and its specifications are as follows:Rated input = 125 volts, 16 ampsArmature Resistance = 0.3 ohms(Ω)Shunt Field Resistance = 50 ohms (Ω)Series Field Resistance 0.6 ohms (Ω)Rheostat Resistance = 12.5 ohms (Ω)A)power consumed by series field(P-series)a)56.58W b)153.6W c)265.42W d)1523.WB)power consumed by shunt field(P-shunt)a)56.58W b)153.6W c)265.42W d)1523.56WC)power consumed by armature resistance(P-arm)a)56.58W b)153.6W c)265.42W d)1523.56WD)percent efficiency of the machine( % eff) if rotational loses are 850 Wa)30% b)64% c)86% d)99%
A 220V d.c shunt motor is having armature current of 10 A and torque of 10 N-m.Find the torque when armature current is doubled a. 5 N-m b. 10 N-m c. 40 N-m d. 20 N-m