The answers were already given.a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 54.9124°h. v(t) = 98.9949sin(20πt - 54.9124°)i. 29.0880 Vj. 108.8253°k. 66.8639 ms 1.A 70-Vac source has the following waveform. Determine:a.Vpkb. Vpk-pkC.Vrmsd. Periode. FrequencyAngular Velocityg. Phase Anglef.هنهنهh.i.j.equation of the waveform (in time domain)the instantaneous voltage when t = 120 msthe angle (1st occurrence) after t = 0 when thevoltage is +80 Vk.the time (2nd occurrence) after t = 0 when thevoltage is -10 Vφ180 VNA50 ms -

Given a 70V AC source waveform (Vrms = 70V) Asked for the following Vpk Vpk-pk Vrms Period…

1. A 70-Vac source has the following waveform. Determine: a. Vpk b. Vpk-pk C. Vrms d. Period e. Frequency f. Angular Velocity g. Phase Angle h. i. j. equation of the waveform (in time domain) the instantaneous voltage when t = 120 ms the angle (1st occurrence) after t = 0 when the voltage is +80 V k. the time (2nd occurrence) after t = 0 when the voltage is -10 V 180 V NA <<-50 ms

1. A 70-Vac source has the following waveform. Determine: a. Vpk b. Vpk-pk C. Vrms d. Period e. Frequency f. Angular Velocity g. Phase Angle h. i. j. equation of the waveform (in time domain) the instantaneous voltage when t = 120 ms the angle (1st occurrence) after t = 0 when the voltage is +80 V k. the time (2nd occurrence) after t = 0 when the voltage is -10 V 180 V NA <<-50 ms

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.13MCQ

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If the rms phasor of a voltage is given by V=12060 volts, then the corresponding v(t) is given by (a) 1202cos(t+60) (b) 120cos(t+60) (c) 1202sin(t+60)
Give the solution for J and K ONLY ans (0.99959 degrees and 63.643 ms respectively).Read A 70-Vac source has the following waveform. Determine:a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angleh. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms
Read A 70-Vac source has the following waveform. Determine:a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angleh. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms Give the solution for J and K ONLY ans (0.99959 degrees and 63.643 ms respectively)
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