Please answer number 1 #81. A charge of 6.90 nC is placed in a uniform electric field that is directed vertically upwardwith a magnitude of 0.69 MN (MegaNewton)/C. What work is done by the electrical forcewhen the charge moves 0.690 m to the left? 0.690 m upwards? 2.30 m at an angle of 23degrees from the horizontal?2. The temperature near the center of a particular star is thought to be 10 Million degreesCelsius. Through what voltage must a singly charged ion be accelerated to have the sameenergy as the average kinetic energy of ions at this temperature? What is the potentialenergy needed to have this kind of voltage?Use this formula: Average Kinetic Energy (KE) = 3/2 *k*T; V = U/q0you must equate U and KE to find V and in the formula of KE, k = 1.38 x10^-23 J/K%3DWhere(Boltzmann constant for ideal gas) and T = temperature given= electron charge 1.6 x 10^-19 C

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1. A charge of 6.90 nC is placed in a uniform electric field that is directed vertically upward with a magnitude of 0.69 MN (MegaNewton)/C. What work is done by the electrical force when the charge moves 0.690 m to the left? 0.690 m upwards? 2.30 m at an angle of 23 degrees from the horizontal?

1. A charge of 6.90 nC is placed in a uniform electric field that is directed vertically upward with a magnitude of 0.69 MN (MegaNewton)/C. What work is done by the electrical force when the charge moves 0.690 m to the left? 0.690 m upwards? 2.30 m at an angle of 23 degrees from the horizontal?

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Please answer number 1

#8
1. A charge of 6.90 nC is placed in a uniform electric field that is directed vertically upward
with a magnitude of 0.69 MN (MegaNewton)/C. What work is done by the electrical force
when the charge moves 0.690 m to the left? 0.690 m upwards? 2.30 m at an angle of 23
degrees from the horizontal?
2. The temperature near the center of a particular star is thought to be 10 Million degrees
Celsius. Through what voltage must a singly charged ion be accelerated to have the same
energy as the average kinetic energy of ions at this temperature? What is the potential
energy needed to have this kind of voltage?
Use this formula: Average Kinetic Energy (KE) = 3/2 *k*T; V = U/q0
you must equate U and KE to find V and in the formula of KE, k = 1.38 x10^-23 J/K
%3D
Where
(Boltzmann constant for ideal gas) and T = temperature given
= electron charge 1.6 x 10^-19 C

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