Note,the conversion from mm to m is 10^-3 1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gaugelength of 20.31 mm is pulled in tension. Use the load-elongation characteristicstabulated below to answer the following questions;Load Length(N)(mm)20.3120.381220.451820.512420.553020.613620.6442.820.6848.920.7255.220.766020.7965.820.8470.720.8777.320.9383.1 20.9888.622.1591.5823.2491.68 25.4106ChangeinlengthLength (x10-2 m) (m)Computed strain Computed stress (N/m²)(a) Compute the cross-sectional area of brass.(3

Given: Let us consider the given data, Radius, r=3.8×10-2 m Length, l=20.31 mm To find: The…

1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gauge length of 20.31 mm is pulled in tension. Use the load-elongation characteristics tabulated below to answer the following questions; Load Length (N) (mm) 0 20.31 6 20.38 12 20.45 18 20.51 24 20.55 30 20.61 36 20.64 42.8 20.68 48.9 20.72 55.2 20.76 60 20.79 65.8 20.84 70.7 20.87 77.3 20.93 83.1 20.98 88.6 22.15 91.58 23.24 91.68 25.41 Change in length Length (x10-2 m) (m) Computed strain Computed stress (N/m²) (a) Compute the cross-sectional area of brass. (3

1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gauge length of 20.31 mm is pulled in tension. Use the load-elongation characteristics tabulated below to answer the following questions; Load Length (N) (mm) 0 20.31 6 20.38 12 20.45 18 20.51 24 20.55 30 20.61 36 20.64 42.8 20.68 48.9 20.72 55.2 20.76 60 20.79 65.8 20.84 70.7 20.87 77.3 20.93 83.1 20.98 88.6 22.15 91.58 23.24 91.68 25.41 Change in length Length (x10-2 m) (m) Computed strain Computed stress (N/m²) (a) Compute the cross-sectional area of brass. (3

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. Question 1 ;Determine the elastic energy absorption capacity (in N.mm) of that specimen. Question 2; Determine the plastic energy absorption capacity (in N.mm) of that specimen.
Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Determine the true stress (in MPa) at yield point. - Determine the true stress (in MPa) at point of ultimate strength. - Determine the true stress (in MPa) at fracture point. - Determine the true strain (in mm/mm) at yield point. (Use at least five decimal units) - Determine the true strain (in mm/mm) at point of ultimate strength. (Use at least five decimal units) - Determine the true strain (in mm/mm) at fracture point. (Use at least five decimal units)
In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph.
In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph. Answer: breaking stress,true stress at fracture and limit of proportionality.
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I want answers to all four questions if possible. Thanks for help :) Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Calculate the fracture strength (in MPa) of the material. - Calculate the percent elongation of the specimen at fracture point. - Determine the modulus of resilience (in N.mm/mm3) of the material. (Use at least five decimal units) - Determine the toughness index number (in N.mm/mm3) of the material.
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The following data were obtained during a tensile test of an alluminium alloy specimen. Initial diameter = 18mm Original gauge length = 45mm Final gauge length = 53mm Load at elastic limit = 82kN Yield load = 93kN Maximum load = 168kN Determine the Yield stress - answer to be provided in MPa correct to 3 decimal
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In a Torsion test done, the following data were collected: the radius of the specimen was 3mm and the gauge length 76.2mm. During the elastic zone: T1-0. 01N.m. 01-14.760, T2-17. 13N.m, and 02-36.910. The modulus of rigidity be equal to: