1. A disk of radius 0.10 m is oriented with its normal unit vector î is anti-parallel with the uniform electric field E of r= 0.10 m magnitude 2.0 x 10³ N/C. (Since this isn't a closed surface, it has no "inside" or "outside." That's why we have to 30° specify the direction of in the figure.) What is the electric flux through the disk? 2. An imaginary cubical surface of side L is in a region of uniform electric field E. Find the electric flux through each face of the cube and the total flux through the cube when the cube is turned by an angle e about a vertical axis. 90° – 0

1. A disk of radius 0.10 m is oriented with its normal unit vector î is anti-parallel with the uniform electric field E of r= 0.10 m magnitude 2.0 x 10³ N/C. (Since this isn't a closed surface, it has no "inside" or "outside." That's why we have to 30° specify the direction of in the figure.) What is the electric flux through the disk? 2. An imaginary cubical surface of side L is in a region of uniform electric field E. Find the electric flux through each face of the cube and the total flux through the cube when the cube is turned by an angle e about a vertical axis. 90° – 0

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

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