1. A rocket is being launched vertically over a point A on the ground with a velocity of 550 mi/hr. Twenty-five miles away from point A on the ground, there is a photographer video-taping the launch. At what rate is the angle of elevation of the camera changing when the rocket achieves an altitude of 25 miles?

Q: A 10-ft ladder is leaning against a house when its base starts to slide away. By the time the base…

A: Length of ladder is l= 10ft X=8 ft, dx/dt= 18ft/sec From the fig l =[ x2 + y2 ]0.5= 10 a) from…

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A: According to our guidelines, In case of multiple questions we are supposed to answer the first…

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A: given: A 15-meter ladder is resting against a vertical wall. the bottom of the ladder is being…

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A: a)  Given that the balloon is in the shape of sphere and it is being inflated at the rate of…

Q: A    26    foot    ladder    is    sliding    down    a    vertical    wall.        The    base…

A:

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A: Given that

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A: Please see the explanation below

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Q: 1. A 25-ft ladder is leaning against a house when its base starts to slide away. By the time the…

A:

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A: dy/dt = rate of moving of tip of shadow dp/dt = rate of change in length of shadow

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A: Solve to the given question condition

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A: Given:         Length of ladder =20 ft    dhdt=-2 ft/sec

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A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

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A:

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A:

Q: A 15-meter ladder is resting against a vertical wall, If the bottom of the ladder is being pushed…

A: Let ladder AB, l=15 m, Ladder is pushed horizontally at the rate of 1.5 m/s, ⇒dydt=1.5 We need to…

Q: If a ladder of length 20 ft which is leaning against a vertical wall has its upper end sliding down…

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A: The problems involves the differentiation to find the respective values. Differentiation is defined…

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A: The given data is: A man 6 feet tall walks at a rate of 7 feet per second away from a light that is…

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A: Given : Length of the ladder = 20 ft

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A: Consider h is the height, and b is the base, ladder's length be 'L' apply the Pythagoras theorem,…

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A: We need to find rate of distance changing.   ddθ(cscθ)=-csc(θ)cot(θ)

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A: Let OA= height of light      CD= height of man      BC= length of shadow…

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A: We'll answer one question since the exact one hasn't specified. Please re-submit the question you…

Q: A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the…

A:

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