1. An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (ft./s). The height of the object off the ground is given by the formula h(t) = - 16+45t+75, where h(t) is the object's height at time (t) seconds after the object is propelled. The downward negative pull on the object is represented by16t. - Solve for t.

1. An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (ft./s). The height of the object off the ground is given by the formula h(t) = - 16+45t+75, where h(t) is the object's height at time (t) seconds after the object is propelled. The downward negative pull on the object is represented by16t. - Solve for t.

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter4: Work And Energy

Section4.2: Kinetic Energy And Potential Energy

Problem 4.1CE

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