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- Two lead spheres are separated by 0.207 m, centre-to-centre. One sphere has a mass of 5.53 kg. The gravitational attraction between the spheres is 6.06x108N. What is the mass of the other sphere? Express your result in SI units but don't include the units in your answer.Assume the earth's mass is 85.47 x 1025 kg, and radius is 51.93 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a low Earth orbit? Let G be the universal gravitational constant and mp be the mass of the planet a satellite is orbiting. Which equation could be used to find the velocity of the satellite if it is placed in a low Earth orbit? Gue (13,522 km| Gm (7,324km| Gm (42,164 kI / Gue (48,115 km|'
- 1. Mamut is standing in the lunch line 6.38 x 106m from the center of Earth. Earth’s mass is 5.98 x 1024kg. What is his acceleration due to gravity? 2. A 3.25 x 1019kg space station has a gravitational acceleration of 4.1 m/s/s from Earth. How far away is the space station? 3. Suppose that two objects attract each other with a gravitational force of 20 units. If the distance between the two objects is halved, what is the new force of attraction between the two objects? 4. Fred is very concerned about his weight but seldom does anything about it. After learning about Newton's law of universal gravitation in Physics class, he becomes all concerned about the possible effect of a change in Earth's mass upon his weight. During a (rare) free moment at the lunch table, he speaks up "How would my weight change if the mass of the Earth increased by 10%?" How would you answer Fred?Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation F=Gm1m2r2F=Gm1m2r2, where FFF is the magnitude of the gravitational attraction on either body, m1m1m_1 and m2m2m_2 are the masses of the bodies, rrr is the distance between them, and GGG is the gravitational constant. In SI units, the units of force are kg⋅m/s2kg⋅m/s2, the units of mass are kgkg, and the units of distance are mm. For this equation to have consistent units, the units of GGG must be which of the following? View AvThe International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 14.137 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.
- What is the total gravitational potential energy of the three masses in (Figure 1)? Assume m1=20kg, m2=15kg and m3=10kg.Earth and Jupiter being separated by a distance = 5.88 x 10^11 m when they are closest a). Use Newton's Universal Gravitation equation to determine the gravitational force of attraction between earth and Jupiter at that distance given G= 6.7 x 10^-11 N x m^2/kg^2, mass of earth = 6 x 10^24 kg, mass of Jupiter = 1.9 x 10^27 kg2 700kg masses (1543lb) are separated by a distance of 30m. Use newton's law of gravitation find the magnitude of the gravitational force exerted by one mass on the other. Where G = 6.67 x 10^-11 N m^2/ kg^2 Please solve
- The International Space Station (ISS) completes one orbit of Earth in 92 minutes. What is the radius of the orbit in kilometers (km)? You may assume the orbit is circular. The mass of the ISS is 420 kg, and the mass of the Earth is 6.0×10246.0×1024kg. Newton’s gravitational constant is 6.7×10−11N⋅m2kg26.7×10−11kg2N⋅m2.The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 1024 kg, the period of the ISS at the orbit around the earth is 2.00 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10-11 Nm2/kg2. Wirte answer in pure numbers.Why, if the sun is so much more massive than the moon, isn’t it responsible for the Tides? Use Universal Law of Gravitation to explain.