1. Calculate the mass-volume percent of a solution made by dissolving 22.0 g of CH3OH (methanol) in C₂H5OH (ethanol) to make 100. mL of solution. answer: 22.0% m/v What is the volume percent of 10.0 mL of methanol dissolved in water to a volume of 40.0 mL? 2. answer: 25.0 % V/V 3. If I have 125 grams of a 2.5 % (m/m) solution of NaCl, how many grams of NaCl are in this solution? the volume of answer: 3.1 g NaCl solution from a 12 C) solution.

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Chapter11: Properties Of Solutions
Section: Chapter Questions
Problem 138CP: Specifications for lactated Ringers solution, which is used for intravenous (IV) injections, are as...
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answer: 0.0750 mol H₂SO4
8. Calculate the grams of solute in 150 L of a 1.0 M NaCl solution.
answer: 8800 g NaCl (8766)
9.
answer: 1048 mL soln
10.
12.
How many milliliters of 0.2560 M KCI solution will contain 20.00 g of KCI?
propo
answer: 99 mL
BaCl₂ (aq) + K₂CrO4 (aq) → BaCrO4 (s) + 2 KCI (aq)
Using the above equation, calculate:
Calculate the volume of concentrated reagent required to prepare 225. mL of a
5.28 M HCl solution from a 12 M HCI solution.
a.
b.
M H₂SO4 solution.
answer: 7.60 g BaCrO4
4160
the grams of BaCrO4 that can be obtained from 100.0 mL of 0.300 M
BaClz.
answer: 0.015 L BaCl₂ solution
p
The volume of 1.0 M BaCl₂ solution needed to react with 50.0 mL of 0.300
M K₂CRO4 solution.
Transcribed Image Text:answer: 0.0750 mol H₂SO4 8. Calculate the grams of solute in 150 L of a 1.0 M NaCl solution. answer: 8800 g NaCl (8766) 9. answer: 1048 mL soln 10. 12. How many milliliters of 0.2560 M KCI solution will contain 20.00 g of KCI? propo answer: 99 mL BaCl₂ (aq) + K₂CrO4 (aq) → BaCrO4 (s) + 2 KCI (aq) Using the above equation, calculate: Calculate the volume of concentrated reagent required to prepare 225. mL of a 5.28 M HCl solution from a 12 M HCI solution. a. b. M H₂SO4 solution. answer: 7.60 g BaCrO4 4160 the grams of BaCrO4 that can be obtained from 100.0 mL of 0.300 M BaClz. answer: 0.015 L BaCl₂ solution p The volume of 1.0 M BaCl₂ solution needed to react with 50.0 mL of 0.300 M K₂CRO4 solution.
1. Calculate the mass-volume percent of a solution made by dissolving 22.0 g of
answar CH3OH (methanol) in C₂H5OH (ethanol) to make 100. mL of solution.
answer: 22.0% m/v
What is the volume percent of 10.0 mL of methanol dissolved in water to a
volume of 40.0 mL?
2.
answer: 25.0 % v/v
6.
3. If I have 125 grams of a 2.5 % (m/m) solution of NaCl, how many grams of NaCl
answer are in this solution?
4.
5.28 M HC solution from a 12 M HCl solution.
answer: 3.1 g NaCl
5.
answer: 214 mL solution
** KC solution will contain 20.00 g of KC?
What volume of 70.0% rubbing alcohol can you prepare if you have only 150. mL
of pure isopropyl alcohol on hand?
BaCl₂ (aq) + K₂CO (aq) → BaCrO (s) + 2 KCl (aq)
answer: 4.5 g NaCl
Physiological saline, NaCl, solutions have a concentration of 0.90% NaCl (m/v),
How many grams of NaCl are needed to prepare 500.0 mL of this solution?
The volume of 1.0 M BlaCly sol
Calculate the molarity of a solution that contains 2.5 moles of NaCl in 0.650 L of
solution.
answer: 3.8 M NaCl
Transcribed Image Text:1. Calculate the mass-volume percent of a solution made by dissolving 22.0 g of answar CH3OH (methanol) in C₂H5OH (ethanol) to make 100. mL of solution. answer: 22.0% m/v What is the volume percent of 10.0 mL of methanol dissolved in water to a volume of 40.0 mL? 2. answer: 25.0 % v/v 6. 3. If I have 125 grams of a 2.5 % (m/m) solution of NaCl, how many grams of NaCl answer are in this solution? 4. 5.28 M HC solution from a 12 M HCl solution. answer: 3.1 g NaCl 5. answer: 214 mL solution ** KC solution will contain 20.00 g of KC? What volume of 70.0% rubbing alcohol can you prepare if you have only 150. mL of pure isopropyl alcohol on hand? BaCl₂ (aq) + K₂CO (aq) → BaCrO (s) + 2 KCl (aq) answer: 4.5 g NaCl Physiological saline, NaCl, solutions have a concentration of 0.90% NaCl (m/v), How many grams of NaCl are needed to prepare 500.0 mL of this solution? The volume of 1.0 M BlaCly sol Calculate the molarity of a solution that contains 2.5 moles of NaCl in 0.650 L of solution. answer: 3.8 M NaCl
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