1. Electrostatic force is inversely proportional to the square of the distance between two charges. 2. The magnitude of a positive test charge is inversely proportional to the electric field. F = kqıq2 а. r2 3. Electric field is directly affected by the electrostatic force. 4. The electrostatic force between b. En = k Q r2 is directly charges proportional to the product of the magnitude of charges. 5. The electric field at a point is inversely proportional to the square of the distance of the point two E = E с. qo

1. Electrostatic force is inversely proportional to the square of the distance between two charges. 2. The magnitude of a positive test charge is inversely proportional to the electric field. F = kqıq2 а. r2 3. Electric field is directly affected by the electrostatic force. 4. The electrostatic force between b. En = k Q r2 is directly charges proportional to the product of the magnitude of charges. 5. The electric field at a point is inversely proportional to the square of the distance of the point two E = E с. qo

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 52P: Suppose Earth and the Moon each carried a net negative charge Q . Approximate both bodies as point...

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Suppose Earth and the Moon each carried a net negative charge Q . Approximate both bodies as point masses and point charges. (a) What value of Q is required to balance the gravitational attraction between Earth and the Moon? (b) Does the distance between Earth and the Moon affect your answer? Explain. (c) How many electrons would be needed to produce this charge?
Find the ratio of the electrostatic to gravitational force between two electrons. (b) What is this ratio for two protons? (c) Why is the ratio different for electrons and protons?
A test charge of +2C is placed halfway between a charge of +6 C and another of +4 /C separated by 10 cm. (a) What is the magnitude of the force on the test charge? (b) What is the direction of this force (away from or toward the +6 C charge)?
Part 1: What is the magnitude of the net electric fieldat the position of the charge at the origin?Answer in units of N/C. Part 2: What is the direction of the net electric field(as an angle between −180◦and +180◦ measured from the positive x-axis, with counterclockwise positive).Answer in units of ◦.
Two 4.0 kgkg masses are 1.0 mm apart on a frictionless table. Each has 1.0 μCμC of charge. Part A What is the magnitude of the electric force on one of the masses? Part B What is the initial acceleration of each mass if they are released and allowed to move? Express your answer in meters per second squared.
The following unit is certainly not the standard unit for expressing the quantity electric field strength. kg • m / s2 / C However, it could be an acceptable unit for E. Use unit analysis to identify whether the above set of units is an acceptable unit for electric field strength.
When you pet a cat, you rub electrons off the cat’s fur, which aretransferred to your hand. Assuming that you transfer 5 x10 10 electrons toyour hand:a) What’s the electric charge on your hand?b) What’s the electric charge on the cat?
An electron has an initial velocity of 3×10to6 m/s in the +x direction. It enters a uniform electric field E = 418 N/C which is in the +y direction. By how much, and in what direction, is the electron deflected after traveling 11 cm in the +x direction in the field? (Express the direction of deflexion by using positive and negative signs. Your result must be in cm's and include 1 digit after the decimal point. Maximum of 5% of error is accepted in your answer. Take elementary charge 1.6x10to-19 C and mass of electron 9.1x10-31 kg.)
1. What is the electric field due to a point of 15μC at a distance of 1 meter away from it? 2. What is the electric field strength at a distance of 10 cm from a charge of 2μC? 3. What is the electric field strength at a distance of 130 cm from a charge of 5.2 μC?
A positive charge of 0.0001014 C experiencesa force of 0.197 N when located at a certainpoint.What is the electric field magnitude at thatpoint?Answer in units of N/C
Q3) with velocity (9 x 10° m/s) an electron enters the uniformly electric field of parallel plate perpendicular to the fied fine the distance between two plate d=50 mm and the length of the plates are 65mm and the electric field between the plates is 3000 N/c 1 2) 3 4 s ‘Whatis the acceleration of electron in Y-direction? How much time dose it takes for the electron to move through the plate? How far from the x-axis the electron is when it leaves the plates? ‘Whatis the velocity of electron in y- direction when it leaves the electric ield? Determine the angle that the velocity of electron makes with the x-axis when it leaves the electrc field?
A mass of 1.2 mg with a charge of 2.31*10-3 C experiences an electric force of .0510 N directed westward. a) What is the electric field in the region? b) What is the acceleration experienced by the mass? c) If the mass of the charge is doubled to 2.4 mg, what is the force? d) If the charge on the mass is changed to -1.44*10-6 C, what is the force on the charge?