1. In the system in Figure E.1, x,(t) = sinc(t), fc = 10 and the cutoff frequency of the lowpass filter is 1 Hz. Graph the signals x, (t), y,(t), ya(t) and yf(t) and the magnitudes and phases of their CTFTS. y,(1) = x,(1) Ya(t) x,(1) LPF cos(2f1) cos(21ft)

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Signals and systems Please solve for problem. 7 only Based on the problem 1.
1. In the system in Figure E.1, x,(t) = sinc(t), fe
the lowpass filter is 1 Hz. Graph the signals x, (t), y,(t), ya(t) and yƒ(t) and the
magnitudes and phases of their CTFTS.
= 10 and the cutoff frequency of
y,(1) = x,(1)
Ya(1)
x,(1)
- y,(1)
LPF
cos(2nfct)
cos(2tft)
Figure E.1
Transcribed Image Text:1. In the system in Figure E.1, x,(t) = sinc(t), fe the lowpass filter is 1 Hz. Graph the signals x, (t), y,(t), ya(t) and yƒ(t) and the magnitudes and phases of their CTFTS. = 10 and the cutoff frequency of y,(1) = x,(1) Ya(1) x,(1) - y,(1) LPF cos(2nfct) cos(2tft) Figure E.1
Chapter 12 Communication System Analysis
EXERCISES WITHOUT ANSWERS
Amplitude Modulation
7. Repeat Exercise 1 but with the second cos(2Tfet) replaced by sin(2ifct).
Transcribed Image Text:Chapter 12 Communication System Analysis EXERCISES WITHOUT ANSWERS Amplitude Modulation 7. Repeat Exercise 1 but with the second cos(2Tfet) replaced by sin(2ifct).
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Given the system a shown below:

Electrical Engineering homework question answer, step 1, image 1

xt(t)=sinc(t), fc=10 and the cut-off frequency of the low-pass filter is 1 Hz. We need to plot the signals xt(t) , yt(t), yd(t) and yf(t) and the magnitudes and phases of their CTFT's.

 

 

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