1. In this experiment, aluminum will be converted into potassium aluminum sulphate dodecahydrate. This process requires three reactions. Balance these three reactions. A] Al (s) + KOH (aq) + HOH (1) = KAI(OH)4 (aq) + H2 (a) B] KAI(OH)4 (aq) + H2SO4 (aq) = KAI(SO4)2 (aq) + H2O 0) c] KAI(SO42 (aq) + H2O (1) KAI(SO4)2 • 12 H20 (9)

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Chapter3: Stoichiometry
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Could someone help me balance these three reactions in #1?
1. In this experiment, aluminum will be converted into potassium aluminum sulphate
dodecahydrate. This process requires three reactions. Balance these three reactions.
A]
Al (s) + KOH (aq) + HOH (1)
KAI(OH)4 (aq) + H2 (a)
B]
KAI(OH)4 (aa)
+ H2SO4 (aq) >
KAI(SO:)2 (aq) + H2O )
C]
KAI(SO42
+ H2O (1)
KAI(SO4)2 • 12 H20 (9)
(aq)
2. Under experimental procedures #2 and #3, the experiment calls for reacting
aluminum with water and potassium hydroxide. See 1A above for the equation. A
student used the following quantities:
3.00 grams Al
15.0 mL of 8.00 M KOH
75.0 mL of distilled HOH
Which of the reactants is the limiting reactant? (Mathematically document this.)
Show your work and set-up.
D.
Transcribed Image Text:1. In this experiment, aluminum will be converted into potassium aluminum sulphate dodecahydrate. This process requires three reactions. Balance these three reactions. A] Al (s) + KOH (aq) + HOH (1) KAI(OH)4 (aq) + H2 (a) B] KAI(OH)4 (aa) + H2SO4 (aq) > KAI(SO:)2 (aq) + H2O ) C] KAI(SO42 + H2O (1) KAI(SO4)2 • 12 H20 (9) (aq) 2. Under experimental procedures #2 and #3, the experiment calls for reacting aluminum with water and potassium hydroxide. See 1A above for the equation. A student used the following quantities: 3.00 grams Al 15.0 mL of 8.00 M KOH 75.0 mL of distilled HOH Which of the reactants is the limiting reactant? (Mathematically document this.) Show your work and set-up. D.
Expert Solution
Step 1

A)The reaction taking place is given as,

=> Al (s) + KOH (aq) + HOH (l) ------> KAl(OH)4 (aq) + H2 (g)

 

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