1.) IS THE POSSIBLE SWING MA XIMI ZED? a-) YES. THE SELECTED VALUE OF Vour IS EXACTLY HAF of THE SUPPLY RANGE. B.) VET. THE VorsAt Of EAlH TRANSISTOR ARE EQUAL of VALUE MIOWNG MAXIMUM OWING AT THE GIVEN VAUE OF Vour· c) NO. THE TRANSISTORS HAVE DIFFERENT PROPERTIES TO BEGIN WITH 8o BOTH CAN'T BE BIASEO n STURATION REGION AT THE SAME TIN'E.

EBK ELECTRICAL WIRING RESIDENTIAL
19th Edition
ISBN:9781337516549
Author:Simmons
Publisher:Simmons
Chapter25: Television, Telephone, And Low-voltage Signal Systems
Section25.2: Telephone System
Problem 2R: At what height are the telephone outlets in this residence mounted? Give measurement to center....
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Q UESTIO NS:
1.) IS THE POSSIBLE SWING MA XIMI 2ED?
a.) YES. THE SELECTED VALUE OF Vour I5 EXACTLY HME OF
THE SUPPLY RANGE.
B.) VET. THE Vorsar Of EACH TRANSISTOR ARE EQUAM of
VALUE ALLOWING MAXIMUM owING AT TH GIVEN VAUE
OF Vour
G) NO. THE TRANSISTORS HAVE DIFFERENT PROPERTIES TO
BEGIN WITH 8o BOTH CAN'T BE BIASEO SATURATION
REBION AT THE
SAME TIN'E .
Transcribed Image Text:Q UESTIO NS: 1.) IS THE POSSIBLE SWING MA XIMI 2ED? a.) YES. THE SELECTED VALUE OF Vour I5 EXACTLY HME OF THE SUPPLY RANGE. B.) VET. THE Vorsar Of EACH TRANSISTOR ARE EQUAM of VALUE ALLOWING MAXIMUM owING AT TH GIVEN VAUE OF Vour G) NO. THE TRANSISTORS HAVE DIFFERENT PROPERTIES TO BEGIN WITH 8o BOTH CAN'T BE BIASEO SATURATION REBION AT THE SAME TIN'E .
5V
THE CURCUET
ONTHE
LEFT IS BASED SUCH
THAT Vour 2.5 V. GIVON THE FOLLOWING
VBIAS
M2
TRANSISTOR PROPERTIO:
mA
kp: 10. 25
an pl
Kn :
Vout
0.7 V
: 0.5V
dp= 0.04 +
: 0. 01
Vin
COMMON SOURCE WITH ACTIVE LOND
Transcribed Image Text:5V THE CURCUET ONTHE LEFT IS BASED SUCH THAT Vour 2.5 V. GIVON THE FOLLOWING VBIAS M2 TRANSISTOR PROPERTIO: mA kp: 10. 25 an pl Kn : Vout 0.7 V : 0.5V dp= 0.04 + : 0. 01 Vin COMMON SOURCE WITH ACTIVE LOND
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EBK ELECTRICAL WIRING RESIDENTIAL
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Electrical Engineering
ISBN:
9781337516549
Author:
Simmons
Publisher:
CENGAGE LEARNING - CONSIGNMENT