Part1: Resistors connected in series to each otherThe circuit shown below was generated on MapleSIM 2019Voltmeter 1Voltmeter 2Voltmeter 3Ammeter 2Ammeter 1RI=25OhmsR2=500hmsR3=750hmsAmmeter 36VThe response of this circuit, i.e., the values of the probes measuring voltages and currents wassimulated for a total time of 10s. The simulated data is shown below* Analysis Window: Simulation ResultsE Probe Pluts- Simulation ResultsV Stored ResultsAmmeter 3iAmmeter liAmmeter 210.0500 050-0 050-0.0450.0450.045-Vanables0 040O 0400 040Find0.035-0.0350.035-MainNo Stored Resut Selected0030-00300 03016411626 7 8Hot Windovs Senes Datas.Veltmeter 1vValtmeter 2yVolmeter 3.v4.5-65ala Probe PlotsE Ammeter JE Aeter 2aB Ammotor 3.1E Voltmeter 1vAv voltmeter Z.v053.5Vettreeter 3.N1.525-05--0.514-211.512101210 In the data above, the units for currents is "A" and for voltages is "V". The Ammeter probes have aleast count of 0.001A or 1mA and the Voltmeters read a least value of 0.1V. The experimentally thedecimal placement implies the precision employed which relates to the significant figures.1. Report the experimental values ofa. The current through R1b. The current through R2C. The current through R3d. Total current through the circuit2. Report the experimental voltage drop/ the voltage difference acrossResistor R1 (Note the voltage drop for R1 =6V-reading on voltmeter 1)a.b. Resistor R2C.Resistor R33. Using Ohm's law and the values specified in the circuit, calculatea. The equivalent resistance and the total current through the circuitb. The voltage drop/ the voltage difference across the resistor R1The voltage drop/the voltage difference across the resistor R2d. The voltage drop/the voltage difference across the resistor R3Does the sum of the voltage drop (energy dissipated) across the resistors add up tothe voltage supplied (energy supplied) by the battery?e.4. Among the two variables (I/ V), which is constant across all the resistors

The solution can be achieved as follows.

Answered: 1. Report the experimental välües of a.…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Objectives: Voltage drop measurements using resistors connected in series. The relationship between resistance value and voltage drop (Kirchhoff’s Second Law) Circuit components: 1 Plug-in board, DIN A4 576 74 1 STE resistor, 100 W, 2 W, 5% 577 32 1 STE resistor, 150 W, 2 W, 5% 577 34 1 STE resistor, 1 kW, 2 W, 5% 577 44 Power Supply: 1 AC/DC stabilizer 726 88 Connectors: 3 Pairs of connecting leads, red/blue, 50 cm 501 45 1 Set of 10 bridging plugs 501 48 Measurement Instruments: 1 Voltmeter, 10 V DC 1 Amperemeter, 10 mA DC Measuring the voltage drop across resistors…
a) A 380V, 7.5kW electric water pump of power factor 0.8 lagging and efficiency of 85% will be wired by an armoured XLPE insulated copper cable. The circuit will be run on cable tray with three other similar circuits at an ambient temperature of 40℃. MCCB will be used as the overcurrent protective device for the circuit. The estimated length of the circuit for the machine is 50m. i) Determine the minimum rating of MCCB for the circuit, available MCCB rating are 25A, 30A, 40A, 50A ii) Determine the minimum cable size of the circuit if the allowable voltage drop of the circuit is 1.5% of the nominal supply voltage?
Please show a complete step-by-step solution. Thank youGive your final answers in at least 2 decimal places - make it 3 or 4 decimal places whenever required in the problem. If you are doing a step by step calculation, maintain 6 decimal places in your in-between calculations to hit good accuracy in your final answers. Use 1 hp = 746 Watts in your conversion whenever necessary. A three-phase,50-Hz, 480-V system supplies the following loads:1. A six-pole, 50-Hz, 460-hp, three-phase, wye-connected induction motor, operating at 71 percent of the rated load with an efficiency of 93.6 percent and a power factor of 87.1 percent.2. A 55-kW, delta-connected, three-phase resistance heater.3. A 200-hp, 50-Hz, four-pole, wye-connected, cylindrical-rotor synchronous motor, operating at 51 percent of the rated load, with a torque angle of -13.2º.Neglecting copper losses, the synchronous motor is operating at 92.4 percent efficiency, and its synchronous reactance is 0.598 Ohm/phase. Determine the…
There are five electric appliances, viz. electric heater, electric lamp, an electric fan,computer and an exhaust fan are connected in parallel in a household. Ther resistanceelectric appliances are 409,522, 80, 200 and 100 respectively. If ane electriccurrent of 240V is flowing through the circuit then find following 1. Evaluate the electric current through heater 2. Determine electric current through electric lamp 3. Find out total resistance of the circuit 4.calculate electric current through circuit 5.evaluate electric current through electric fan
Please show a complete step-by-step solution. Thank youGive your final answers in at least 2 decimal places - make it 3 or 4 decimal places whenever required in the problem. If you are doing a step by step calculation, maintain 6 decimal places in your in-between calculations to hit good accuracy in your final answers. Use 1 hp = 746 Watts in your conversion whenever necessary. A three-phase, 10-hp, 60-Hz, 1600-V, 500 r/min, salient-pole synchronous motor has direct-axis and quadrature-axis reactances equal to 37.10 Ohms/phase and 20.52 Ohms/phase, respectively. Neglecting losses, determine the developed torque if the field current is adjusted so that the excitation voltage is equal to 2.3 times the applied stator voltage, and the power angle is -18º. Give your final answer in 2 decimal places. Correct Answer: 921.26 ± 0.01
In the circuit given in the figure | VBE | Since = 0.7V, R1 = 2.66Kohm, R2 = 11.73Kohm, RC = 0.79Kohm, RE = 2.36Kohm, VCC = 14.00V, Beta = 115.00, calculate the IC current by full analysis. When making your transactions, 2 steps will be taken after the point. Select the closest option according to +/- 10% margin of error. There is only one correct answer to the question.
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choose the correct option 1. If the output of a transistor amplifier is 5 V rms and the input is 100 mV rms, the voltage gain is a) 5 b) 50 c) 500 d) 5000 2. Multimeter can also be used to check whether a circuit is short or open a) True b) False 3. Ohm's law is not applicable to a) DC circuits b) high currents c) small resistors d) semi-conductors 4. In a series circuit with unequal resistances: a) the highest resistance has the most of the current through it b) the lowest resistance has the highest voltage drop c) the lowest resistance has the highest current d) the highest resistance has the highest voltage drop 5) A simple multimeter can be used to test the functional NPN or PNP transistor by checking the conductance of two junctions a) True b) False 6. Zener diode is a a) Voltage regulator…
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a) A moving-coil galvanometer, of resistance 5 Ω,gives a full-scale reading when a current of 15 mApasses through the instrument. Explain, with theaid of circuit diagrams, how its range could bealtered so as to read up to: (i) 5 A; (ii) 150 V.Calculate the values of the resistors required.(b) A uniform potentiometer wire, AB, is 4 mlong and has resistance 8 Ω. End A is connected tothe negative terminal of a 2 V cell of negligibleinternal resistance, and end B is connected to thepositive terminal. An ammeter of resistance 5 Ωhas its negative terminal connected to A and itspositive terminal to a point on the wire 3 m fromA. What current will the ammeter indicate?
A meeting hall in an organization is to be provided with a lighting installation. The hall is 30 m × 20 m × 8 m (high). The mounting height is 5 m and the required level of illumination is 144 lm/m2. Design a lighting system for the hall with the given data. Lumens/watt for 200-W lamp = 12 and Lumens/ watt for 500-W lamp = 16. Utilization coefficient = 0.6 Maintenance factor = 0.75 space/height ratio=1 Using metal filament lamps, estimate the following: Flux Luman output per 200 W lamp Luman output per 500 W lamp Number of 500W lamps required Number of 220W lamps required Draw the spacing layout of these lamps State the reason if any of these 2 lamps cannot be arranged in the hall with the given specification. What is the significance of ‘room surface maintenance factor’ and ‘utilization factor’ in the lighting design
Please show a complete step-by-step solution. Thank youGive your final answers in at least 2 decimal places - make it 3 or 4 decimal places whenever required in the problem. If you are doing a step by step calculation, maintain 6 decimal places in your in-between calculations to hit good accuracy in your final answers. Use 1 hp = 746 Watts in your conversion whenever necessary. A three-phase, 30-hp, 60-Hz, 1900-V, 500 r/min, salient-pole synchronous motor has direct-axis and quadrature-axis reactances equal to 36.38 Ohms/phase and 24.25 Ohms/phase, respectively. Neglecting losses, determine the power, in watts, drawn by the motor if the field current is adjusted so that the excitation voltage is equal to 2.1 times the applied stator voltage, and the load is increased until maximum reluctance torque occurs. Give your final answer in 2 decimal places. Correct Answer: 172,167.36 ± 0.01

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