1. Simplify the following with Identities and K-Maps: xy z + ~x~yz + yz 2. Which of the following is NOT logically equivalent to the rest: 1. wx~y + w~z + wxyz + w~yz 2. w (x + ~y + ~z) 3. w + x + ~y + ^Z 4. wx + w~y + w~z 3. Use K-Maps to simplify each of the following: 1. ~x~y~z + ~xyz + ~xy~z 2. ~x~y~z + ~xy~z + x~y~z + xy~z 3. ~y~z + ~yz + xy~Z
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- 5.01-1. Dijkstra's Algorithm (1, part 1). Consider the network shown below, and Dijkstra’s link-state algorithm to find the least cost path from source node U to all other destinations. Using the algorithm statement and its visual representation used in the textbook, complete the first row in the table below showing the link state algorithm’s execution by matching the table entries (a), (b), (c), and (d) with their values.5.01-2. Dijkstra's Algorithm (1, part 2). Consider the network shown below, and Dijkstra’s link-state algorithm to find the least cost path from source node U to all other destinations. Using the algorithm statement and its visual representation used in the textbook, complete the second row in the table below showing the link state algorithm’s execution by matching the table entries (a), (b), (c), (d) and (e) with their values.Create Kmap and then simplify the functions: F(x, y, z) = x′y′z′ + x′yz′ + xy′z′ + xyz′
- Consider a computer with 128 MB of main memory, 64 KB of cache, and 4 bytes per memory block. Find out how to split the address (s-r, r, w) so that it can be used for direct mapping.Find out how to split the address into two parts (s and w) for associative mapping.Find out how to split the address into three parts (s-d, d, and w) for set associative mapping. Assume that each cache set has two lines.4. (a) Suppose the encoding matrix is1−3 − 3 − 40 1 14 3 43Use the encoding matrix above to encode the messageGOOD LUCKUsing 1 for the letter A, 2 for B,….26 for Z and 27 for space.(b) Decode the encoded message(-19, -61, 83, -34, -111, 136, -35, -101, 119,-29,-83,84)using the following decoding matrix10 1 15 − 3 − 1−3 2 13What does the message say?Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. Think about a diagram on k hubs, with numbers from b1 to bk composed on them. For each I from 1 to k: track down such j (1≤j≤k, j≠i), for which (bi⊕bj) is the littlest among all such j, where ⊕ indicates the activity of bitwise XOR (https://en.wikipedia.org/wiki/Bitwise_operation#XOR). Then, draw an undirected edge between vertices with numbers bi and bj in this chart. We say that the succession is acceptable if and provided that the subsequent diagram frames a tree (is associated and doesn't have any straightforward cycles). It is conceivable that for certain numbers bi and bj, you will attempt to add the edge between them twice. All things considered, you will add this edge just a single time. You can track down a model underneath (the image comparing to the main experiment). Succession (0,1,5,2,6) isn't great as we can't arrive at 1 from 5. Notwithstanding,…
- 5.14. SDN implementation of Dijkstra’s algorithm. Consider the implementation of Dijkstra’s algorithm in an SDN framework. Which of the following statements are true? (Hint: more than one statement is true.) Group of answer choices a. When executing, Dijkstra’s algorithm will need to send messages to all of the routers to gather their link costs. b. When executing, Dijkstra’s algorithm will use the link-state database that is maintained within the SDN controller. c. When executing, Dijkstra’s algorithm will execute within the operating system of the SDN controller d. When executing, Dijkstra’s algorithm will run as a network control application “on top” on the SDN controller. e. If a router’s forwarding table should be changed as a result of running Dijkstra’s algorithm, the new flow table for that router will be updated by the SDN controller via the southbound API using the Openflow protocol. f. If a router’s forwarding table should be changed as a result of running Dijkstra’s…Description please. Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [We are expecting a description of the algorithm, as well as a brief justification of its runtime.]Create Kmap and then simplify the functions: F(x, y, z) = y′z′ + y′z + xyz′
- 6.4-6. Self Learning Switches (c). Consider the network below with six nodes, star-connected into an Ethernet switch. Suppose that A sends a frame to A', A’ replies to A, then B sends a message to B’ and B’ replies to B, and then A sends to B and B replies to A. In this sequence of frame transmissions, how many frames have appeared at the interface at C'? Assume that the switch's table is initially empty. [Note: You can find more examples of problems similar to this here.]Mapping is a process in which data is transformed between main memory and cache memory. Consider a computer with main memory capable of storing 1024 K words, each word in memory is 64 bits. The computer has cache memory capable of storing 2048 words, each word is of size 64 bits. Discuss with suitable diagram how associative mapping method can be used to transform data between main memory and cache memory?Please refer to this textbook: “A. Silberschatz, P. B. Galvin and G. Gagne, “Operating System Principles,”7th Edition, John Wiley & Sons Inc., 2006.” And answer the following questions: Question7: A practical way to handle network partitioning is to: (a) Have each process start an election. (b) Elect a leader only if a majority of nodes can be reached. (c) Run a normal election and multicast the result to the subset of processes that can be reached. (d) Divide and conquer: elect multiple coordinators.