Pt. d&e 1. The eye of a hurricane passes over Grand Bahama Island in a direction 30.0° north ofwest with a speed of 42.0 km/h. The hurricane goes this direction for three hours. Then thecourse of the hurricane suddenly shifts due north. From this point, its speed is 27.0 km/hfor two more hours.Convert the velocity vectors to position vectors. Write the position vectors as amagnitude and angle. (remember to measure the angles from the positive x axis)a.30N/w* V:1260km44: ん42 Km h * 3h = 126kmO - 180°30150 0のraa a7kmlh x 2h: 54kmdoplaement NORthb. Assuming Grand Bahama Island is at (0,0), draw a sketch of the two position vectorsrepresenting the path of the hurricane. Remember that North is the positive y axisand that east is the positive x axis.Vz -54 Km300, 0Determine the components of each of the two position vectors.Vly: (63 km (y-cami)176km xsin30 (03kmC.(x-Comp)Vax= Okm (NO x-comp)ix=-109.12 Km-/26とmxco5.30°= 109.12Km7Yay = 54kmd. Add the two vectors to determine the resultant position vector.e.What is the distance from Grand Bahama Island to the final position of thehurricane?

Answered: Image /qna-images/answer/8e497580-4c11-4a56-93bf-cae4194bcdc9.jpg

1. The eye of a hurricane passes over Grand Bahama Island in a direction 30.0° north of west with a speed of 42.0 km/h. The hurricane goes this direction for three hours. Then the course of the hurricane suddenly shifts due north. From this point, its speed is 27.0 km/h for two more hours. Convert the velocity vectors to position vectors. Write the position vectors as a magnitude and angle. (remember to measure the angles from the positive x axis) 30°N/w O - 180° 30 150° 42 Kmh * 3h= 136km * 3h= 126とm %3D Y2 a7km/h x 2h:54km doplacoment NoRth b. Assuming Grand Bahama Island is at (0,0), draw a sketch of the two position vectors representing the path of the hurricane. Remember that North is the positive y axis and that east is the positive x axis. Vz - 54 Km 30 W--- O, 0 Determine the components of each of the two position vectors. Vly: (63 km (y-Comi) 176km xSin30° : (03km C. (x-Comp) Yzx= Okm ( Yix=-109.12 Kkm -/26とmxcos30°=109.12km Yay = 54Km d. Add the two vectors to determine the resultant position vector. e. What is the distance from Grand Bahama Island to the final position of the hurricane?

1. The eye of a hurricane passes over Grand Bahama Island in a direction 30.0° north of west with a speed of 42.0 km/h. The hurricane goes this direction for three hours. Then the course of the hurricane suddenly shifts due north. From this point, its speed is 27.0 km/h for two more hours. Convert the velocity vectors to position vectors. Write the position vectors as a magnitude and angle. (remember to measure the angles from the positive x axis) 30°N/w O - 180° 30 150° 42 Kmh * 3h= 136km * 3h= 126とm %3D Y2 a7km/h x 2h:54km doplacoment NoRth b. Assuming Grand Bahama Island is at (0,0), draw a sketch of the two position vectors representing the path of the hurricane. Remember that North is the positive y axis and that east is the positive x axis. Vz - 54 Km 30 W--- O, 0 Determine the components of each of the two position vectors. Vly: (63 km (y-Comi) 176km xSin30° : (03km C. (x-Comp) Yzx= Okm ( Yix=-109.12 Kkm -/26とmxcos30°=109.12km Yay = 54Km d. Add the two vectors to determine the resultant position vector. e. What is the distance from Grand Bahama Island to the final position of the hurricane?

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 28P: Figure P3.28 illustrates typical proportions of male (m) and female (f) anatomies. The displacements...

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