For multiple choice, choose the best answer. Show all work: indicate your plan and draw FBD's (Free BodyDiagrams), write/label (symbolic) equations (e.g., EF, = 0) before writing numeric equations, box answers.1. The springs on the rope assembly are originally unstretched when 0 = 0°. Determine the tension ineach rope when F = 90 lb. Neglect the size of the pulleys at B and D.B-2 ft-9k= 30 lb/ft9-2 ft-k=30 lb/ft

Draw the free-body diagram of the joint A.

Answered: 1. The springs on the rope assembly are…

1. The springs on the rope assembly are originally unstretched when 0 = 0°. Determine the tension in each rope when F = 90 lb. Neglect the size of the pulleys at B and D. k=30 lb/ft k=30 lb/ft

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter10: Virtual Work And Potential Energy

Section: Chapter Questions

Problem 10.62P: The bar ABC is supported by three identical, ideal springs. Note that the springs are always...

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

For multiple choice, choose the best answer. Show all work: indicate your plan and draw FBD's (Free Body
Diagrams), write/label (symbolic) equations (e.g., EF, = 0) before writing numeric equations, box answers.
1. The springs on the rope assembly are originally unstretched when 0 = 0°. Determine the tension in
each rope when F = 90 lb. Neglect the size of the pulleys at B and D.
B
-2 ft-
9
k= 30 lb/ft
9
-2 ft-
k=30 lb/ft

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