1. Two people start running from rest. The first person has a mass of 59 kg and is wearing dress shoes with a coefficient of static friction of 0.52. The other person is wearing running shoes with a coefficient of static friction of 0.66.™ (a) Calculate the maximum possible initial acceleration of the person wearing dress shoes. [ans: 5.1 m/s² [forward]] (b) Explain why we do not really need the mass of either person when finding the initial maximum possible acceleration. (c) Determine the ratio of the two accelerations and compare it to the ratio of the two coefficients of friction. [ans: 0.79; they are equal]

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
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page 175 q 1

1. Two people start running from rest. The first person has a mass of 59 kg and is wearing
dress shoes with a coefficient of static friction of 0.52. The other person is wearing
running shoes with a coefficient of static friction of 0.66.™
(a) Calculate the maximum possible initial acceleration of the person wearing dress
shoes. [ans: 5.1 m/s² [forward]]
(b) Explain why we do not really need the mass of either person when finding the initial
maximum possible acceleration.
(c) Determine the ratio of the two accelerations and compare it to the ratio of the two
coefficients of friction. [ans: 0.79; they are equal]
Transcribed Image Text:1. Two people start running from rest. The first person has a mass of 59 kg and is wearing dress shoes with a coefficient of static friction of 0.52. The other person is wearing running shoes with a coefficient of static friction of 0.66.™ (a) Calculate the maximum possible initial acceleration of the person wearing dress shoes. [ans: 5.1 m/s² [forward]] (b) Explain why we do not really need the mass of either person when finding the initial maximum possible acceleration. (c) Determine the ratio of the two accelerations and compare it to the ratio of the two coefficients of friction. [ans: 0.79; they are equal]
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