1. Two point charges q; = +26µC and q2 = -17.5µC are 64 cm apart. a. What is the potential energy of the system of two charges? b. What is the electric potential at a point between them 24 cm from q1?
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- A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through.Randomized VariablesE = 2.7 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.7 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.Please answer this question with explanations so I can understand. In a Millikan experiment, two horizontal plates are 2.5 cm apart. A sphere of latex, whose mass is 1.5 X 10-15kg , remains motionless when the difference of potential between the plates is 460 Volts. a) What is the magnitude of the charge on the surface of the latex sphere? b) How many excess or deficient electrons are there on the surface of the sphere?1.The force between 2 identical charges is 40 N. If the distance between the charges increases in double. What will be the value of force? A.10 N B.160 N C.20 N D.80 N 2.Two similar charges are placed in free space and water, with dielectric constant, ε of 1 and 78, respectively. What is the relationship of the electric fields in these 2 medias observables at a point of the distance of 2 cm away? A.Efreespace > Ewater B.Efreespace = Ewater C.78 x Efreespace = Ewater D.Efreespace < Ewater 3.Two-point charges, Q1 and Q2 are located at (0, 0, 0) and (1, 1, 1). If both charges are identical, Q = 15 µC, determine the magnitude of the electric field at (1,1,1). A.25.945 kV/m B.38.695 kV/m C.20.489 kV/m D44.938 kV/m
- In Figure 2, there is a positive charge, +q, at point P(d,0,0).At x=0, there is an infinite conducting sheet which is grounded(V=0). At x=3d, there is a constant surface charge densityρs[C/m2] covering whole y-z plane. Dielectric constant isalso ?1 = ?0 for ? > 3?.Hint: Use image theorem.a) Determine the electric field vectors at point C(x,y,z) where ? ∈ (0,3?).Hint: Be careful of what happens at x=3d.b) Determine the electric field vectors at points A(2d,0,0), B(3d-,0,0), B(3d+,0,0).4) (a)Using the Gauss law find the electric field of an infinite conductor planewith charge density σ.(b)Using the result in part (a) calculate the capacitance of a capacitor made oftwo conducting plane of 2 m2 area and with charge density σ = 9.6 C/m 2 andthese conducting planes are separated with a distance 0.1 mm and there isAluminium oxide as the dielectric between two plates. *Take gravitational constant g =10 m/s2.Fourpointcharges,eachwithchargeq=+2.0nC,arepositionedequidistantlyaroundacircle of radius r = 5.0 cm as shown in figure (A) below. (a) What is the electric field E at C? (b) What is the potential at point C located at the center (assuming V = 0 infintely far away)? If charge q2 is moved to the same position as q4, as shown in figure (B), what are the new (c) electric field E (d) andpotential at point C?
- An electron (q = -e) completes half of a circular orbit of radius r arounda nucleus with Q = +3e, as shown.a. By how much does the electric potential energy change as the electron moves from i to f?b. Is the electron’s speed at f greater than, less than, or equal to its speed at i?An electron is to be accelerated in a uniform electric field having a strength of 264×20°Y What energy in keV is given to the electron if it is accelerated through 0.76m? Could you please show all work and look at correct answerAn oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.0400g droplet hovers motionless when the electric field is set to 370N/C and directed downward. a) What was the charge of the oil droplet in Coulombs? b) Determine the approximate number of excess or defecit electrons on the droplet.
- A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. Randomized Variables E = 2.7 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.7 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.Q3) with velocity (9 x 10° m/s) an electron enters the uniformly electric field of parallel plate perpendicular to the fied fine the distance between two plate d=50 mm and the length of the plates are 65mm and the electric field between the plates is 3000 N/c 1 2) 3 4 s ‘Whatis the acceleration of electron in Y-direction? How much time dose it takes for the electron to move through the plate? How far from the x-axis the electron is when it leaves the plates? ‘Whatis the velocity of electron in y- direction when it leaves the electric ield? Determine the angle that the velocity of electron makes with the x-axis when it leaves the electrc field?I need help with this question: Assume that a stationary electron is a point of charge. What is the energy density u of its electric field at radial distances (a) r = 7.70 mm, (b) r=7.70 µm, (c) r = 7.70 nm, and (d) r = 7.70 pm? (e) What is u in the limit as ? (Select option "1" if or-option "2" if → ∞ See attachment below