1. What is the gravitational force between two 800 kg cars that are 5 m apart? Step 1: set up Newton's Gravity Law formula : F= G( m,)(m,)/r F = Step 2: Use Gravitational Force Calculator and input m1,m2 and distance r Answer: 2. What is the gravitational force between two identical 50,000 kg asteroids whose centers of mass are separated by 1000 m? Step 1: Setup Newton's Gravity Law formula : F = G( m,)(m,)/r² F = Step 2: Use Gravitational Force Calculator and input m1,m2 and distance r Answer:

1. What is the gravitational force between two 800 kg cars that are 5 m apart? Step 1: set up Newton's Gravity Law formula : F= G( m,)(m,)/r F = Step 2: Use Gravitational Force Calculator and input m1,m2 and distance r Answer: 2. What is the gravitational force between two identical 50,000 kg asteroids whose centers of mass are separated by 1000 m? Step 1: Setup Newton's Gravity Law formula : F = G( m,)(m,)/r² F = Step 2: Use Gravitational Force Calculator and input m1,m2 and distance r Answer:

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter13: Gravitation

Section: Chapter Questions

Problem 56P: Consider Figure 13.23 in Tidal Forces. This diagram represents the tidal forces for spring tides....

See similar textbooks

Similar questions

The following question is referring to the concept of Newton’s Law of Gravitation on inferring gravitational force, weight, and acceleration due to gravity and Physical significance of gravitational field. Solve for the unknown quantities and round-off your final answers in the nearest hundredths. 1. Planet A and Planet B have a mass of 4 x 1024 kg and 4.5 x 1025 kg. The gravitational force between the two planets is 4.8 x 1020. How apart is Planet A from Planet B? with step by step explanation.
Consider Figure 13.23 in Tidal Forces. This diagram represents the tidal forces for spring tides. Sketch a similar diagram for neap tides. (Hint: For simplicity, imagine that the Sun and the Moon contribute equally. Your diagram would be the vector sum of two force fields (as in Figure 13.23), reduced by a factor of two, and superimposed at right angles.)
The gravity on Mars is about 38% that of Earth's gravity. Let's say some cargo has a mass of 15 kg here on Earth. First, what would be the weight of that cargo in kilograms on Mars? Explain your answer. Second, what would be the mass of that cargo in kilograms on Mars? Explain your answer.
1. using Newton’s Law of Universal Gravitation and some kinematics calculation we can calculate the mass of the planet. For this, use this equation below: ?planet =(9.340×1024)×(vmax)×(Pstar)1/3×(Mstar)2/3 Given: - vmax = 1.5 m/s - Pstar = 3.5 days - Mstar = 1.148 Msun, where Msun = 1.98847×1030 kg. This calculation is not shown.
F=Gm1m2d2 Calculate the force of gravity on the 0.80-kgkg mass if it were 1.3×107 mm above Earth's surface (that is, if it were three Earth radii from Earth's center).
The International Space Station (ISS) orbits Earth in a nearly circular orbit that is 345 km above Earth's surface. 1) How many hours does it take for the ISS to make each orbit? (Express your answer to three significant figures.) 2) Some of the experiments performed by astronauts in the ISS involve the effects of "weightlessness" on objects. What gravitational force does Earth exert on a 12.0-kg object in the ISS? Express your answer in newtons. (Express your answer to three significant figures.) 3) What gravitational force does Earth exert on a 12.0-kg object in the ISS? Express your answer as a fraction of the force that Earth would exert on the object at Earth's surface. (Express your answer to three significant figures.)
Newton's Law of Gravity is what can we say about the law, and about G? Check the 4 correct statements. There will be partial credit if you miss some. We must find G by making precision experimental measurements because we do not know its value otherwise. All evidence suggests that It is the same everywhere, for all time Its value sets the "size" or "strength" of gravitational force We can calculate G from first principles and understand why it has the value it does. This law of gravity only works near Earth. In space far from Earth there is no gravity. It may not apply very close to very large masses where General Relativity takes over as a better description.
In 1993 the Galileo spacecraft sent home an image of asteroid "243 Ida" and a tiny moon "Dactyl" orbiting the asteroid. Assume that the small moon orbits in a circle with a radius of r = 100 km from the center of the asteroid with an orbital period of T = 27 hours. a. Show and explain how we derived Kepler's 3rd law using Newton's 2nd Law, the definition for centripetal acceleration, and the equation for gravitational force. b. Use your result for Kepler's 3rd Law to determine the mass of the asteroid. c. If the asteroid has a radius of about 16 km calculate the approximate value for the acceleration due to gravity, g, on its surface. d. What velocity would you need to achieve in order to lift off and leave this asteroid? e. Use Newton's 2nd Law, the definition for centripetal acceleration, and the equation for gravitational force to determine an expression for circular orbital velocity. f. What is the orbital velocity of the small moon if we assume it is in a circular orbit?
Explain the folling data regarding artificial gravity. Just explain why these formulas were needed to ultimately find the artificial gravity(4.26 m/s^2)
Please answer the question and subquestions entirely. This is one single question. According to the official guideline, I can ask two subquestions! Thank you! 1) Two bodies, masses m 1 and m 2, attract each other with force F. If one of the masses is doubled, the new gravitational force will be: 2 F F/2 F/4 4 F a) The value of g at an altitude above Earth equal to one Earth diameter is: 9.8 m/s2 4.9 m/s2 2.5 m/s2 1.9 m/s2 1.1 m/s2 b) The escape velocity at the surface of Earth is 11 km/s. What is the escape velocity at the surface of a planet whose radius is 4 times and whose mass is 100 times that of Earth? 1.60 km/s 8 km/s 55 km/s 200 km/s none of the above
(Use Newton’s Law of Gravitational Attraction) A man weighs 160 lb. on the surface of the earth. a) What would he weigh if he were in an airplane flying at an altitude of 50 miles? Hint: you should get a bit less than 160 lb. b) At what altitude above the surface of the earth would the man’s weight be reduced by one half? Express your answer in miles. Use: me = 5.976x1024 kg and re = 6,378 km
How can Kepler's laws of planetary motion and Netwon's Law of universal gravitation be used to describe planetary motion?