1. When a company prices its training seminar at $395 per person, 1,010 people will attend. For each $5 increase in price, there will be 10 fewer people attending. Determine which of the following functions, R(x), must be maximized, as well as on what interval, in order for the company to maximize its revenue (assuming it has a linear price-demand function, where x is the number of people attending the seminar). a) Maximize R(x) = -2x² + 1800x on [0, 1800] b) Maximize R(x) = -0.5x² + 900x on [0, 900] c) Maximize R(x) = -2x² + 1800x on [0, 900) d) Maximize R(x) =-0.5x² +900x on [0, 1800] e) Maximize R(x) = -2x² + 900x on (0,900]

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1. When a company prices its training seminar at $395 per person, 1,010 people will attend. For each $5 increase in
price, there will be 10 fewer people attending. Determine which of the following functions, R(x), must be maximized,
as well as on what interval, in order for the company to maximize its revenue (assuming it has a linear price-demand
function, where x is the number of people attending the seminar).
a) Maximize R(x) = -2x² +1800x on [0, 1800]
b) Maximize R(x) = -0.5x+900x on [0,900]
c) Maximize R(x) = -2x? +1800x on (ò,900]
d) Maximize R(x) =-0.5x +900x on [0, 1800)
e) Maximize R(x) =-2x? +900x on [0, 900]
%3D
Transcribed Image Text:1. When a company prices its training seminar at $395 per person, 1,010 people will attend. For each $5 increase in price, there will be 10 fewer people attending. Determine which of the following functions, R(x), must be maximized, as well as on what interval, in order for the company to maximize its revenue (assuming it has a linear price-demand function, where x is the number of people attending the seminar). a) Maximize R(x) = -2x² +1800x on [0, 1800] b) Maximize R(x) = -0.5x+900x on [0,900] c) Maximize R(x) = -2x? +1800x on (ò,900] d) Maximize R(x) =-0.5x +900x on [0, 1800) e) Maximize R(x) =-2x? +900x on [0, 900] %3D
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