1.2 Problem 2: The current flowing in a given circuit can be described by the function: I(t) = Imax(1 - e-t), 0.8 where Imax = 19 A and t = 2.3 s. 0.6 0.4 0.2 a5 1.5 2 25 3 35 t/t ©theexpertta.com Part (a) At what time in seconds is the current equal to 75% of the maximum current? v Correct! 1 = 3.19 Part (b) How much charge, in coulombs, passes through a point in the circuit as the current increases from 0 to 75% of the maximum current? Q = sin() cos() tan() 7 8. 9 HOME cotan() asin() acos() 4 atan() acotan() sinh() 1 3 cosh() tanh() cotanh() END O Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up!
1.2 Problem 2: The current flowing in a given circuit can be described by the function: I(t) = Imax(1 - e-t), 0.8 where Imax = 19 A and t = 2.3 s. 0.6 0.4 0.2 a5 1.5 2 25 3 35 t/t ©theexpertta.com Part (a) At what time in seconds is the current equal to 75% of the maximum current? v Correct! 1 = 3.19 Part (b) How much charge, in coulombs, passes through a point in the circuit as the current increases from 0 to 75% of the maximum current? Q = sin() cos() tan() 7 8. 9 HOME cotan() asin() acos() 4 atan() acotan() sinh() 1 3 cosh() tanh() cotanh() END O Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up!
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter12: The Solid State
Section: Chapter Questions
Problem 22P: Determine the current generated in a superconducting ring of niobium metal 2.00 cm in diameter when...
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Just Part B, thanks! (Oh just in case a method you try results in it, the answer is not 45.6)
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