ME: I found the promblem on the web site (book:university-physics-with-modern-physics-14th-edition, isbn 9780321973610, chapter 21, question 27.87)
only the charges are different, however I got in to touble with the conclusion. within the Eq give(Part A), the denomiator it equals to zero; at least with my math.
Thanks for the help
-Av
Given:
Two 1.20m nonconducting wires meet at a right angle. One segment carries 2.00 μC of charge distributed uniformly along its length, and the other carries − 2.00 μC distributed uniformly along it, as shown in the figure
Part A:
Find the magnitude of the electric field these wires produce at point P, which is 60.0 cm from each wire
Part B:
-1.20 m_ + + + + + + + + + P 120 m
Consider the figure,
1.20 m + + + + + d 0.6m E 1.20 m VE net
(a) The magnitude of filed due to a line of charge is.
is the line charge density a is the half of the length of the line E d is the distance from P to line 2TEO dda L put ,and a=1 2 L 1 Q 1 4,7TE dd +(L/2) =9x103 Nm2/c2 v 2 x10C 0.6m 1 X V(0.6m) +(1.20 m/2) - 35355 N/C
The magnitude of electric field electric field due to positive and negative charge are same but electric field due to negatively charged wir...
E E_E net = -35355N/ci-35355 N/cj E2 E + net (-35355N/ci)+(-35355N/ci) 5.00 x 104 N/C
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