วัตถุมวล 1.50 kg เคลื่อนที่อยู่บนระนาบ xy ด้วยความเร็ว ที = (4.20i - 3.60 j) m/s จงคำนวณหา โมเมนตัมเชิงมุมของวัตถุ (ในหน่วย kg m /s) เมื่อวัตถุอยู่ที่ตำแหน่ง ท = (1.50 1+ 2.20 ]) m 22.0 k 32.0 k

วัตถุมวล 1.50 kg เคลื่อนที่อยู่บนระนาบ xy ด้วยความเร็ว ที = (4.20i - 3.60 j) m/s จงคำนวณหา โมเมนตัมเชิงมุมของวัตถุ (ในหน่วย kg m /s) เมื่อวัตถุอยู่ที่ตำแหน่ง ท = (1.50 1+ 2.20 ]) m 22.0 k 32.0 k

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Physics And Measurement

Section: Chapter Questions

Problem 1.67AP: A rod extending between x = 0 and x = 14.0 cm has uniform cross-sectional area A = 9.00 cm2. Its...

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