1.5m= D↓C20 kN/m²71=18 kN/m²$1=30°₁=0(20.5mO40.7 m(3)40.7 m -0.7 m 2.6 mP,H₂=6mP.10°H₂=0.7 m12-19 kN/m²$=20°c=40 kN/m²Determine the factor of safety in terms of overturning for this retainingstructure.

Answered: Image /qna-images/answer/079a2797-ff6e-4ea6-8e2b-12e50942368a.jpg

1.5m= D ↓ 20 kN/m² 71-18 kN/m² 41-30 ₁=0 (2) 0.5m → 4 0.7m (3) * C -0.7 m-0.7 m 2.6 m O P, H₂=6 m P. P H₂=0.7 m 72-19 kN/m² 42=20° c=40 kN/m² 10 Determine the factor of safety in terms of overturning for this retaining structure.

1.5m= D ↓ 20 kN/m² 71-18 kN/m² 41-30 ₁=0 (2) 0.5m → 4 0.7m (3) * C -0.7 m-0.7 m 2.6 m O P, H₂=6 m P. P H₂=0.7 m 72-19 kN/m² 42=20° c=40 kN/m² 10 Determine the factor of safety in terms of overturning for this retaining structure.

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter13: Slope Stability

Section: Chapter Questions

Problem 13.28CTP

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Concept explainers

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.

Question

1.5m= D
↓
C
20 kN/m²
71=18 kN/m²
$1=30°
₁=0
(2
0.5m
O
4
0.7 m
(3)
4
0.7 m -0.7 m 2.6 m
P,
H₂=6m
P.
10°
H₂=0.7 m
12-19 kN/m²
$=20°
c=40 kN/m²
Determine the factor of safety in terms of overturning for this retaining
structure.

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