1.8 Use the GCD test to determine whether dependences exist in the following loop: for (i = 0; i < 100; i = i + 1) { X[2 i +3] = X[2 * i] * 5.0; } bored cache C
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![1.8
Use the GCD test to determine whether dependences exist in the
following loop:
for (i = 0; i < 100; i = i + 1)
{
X[2 i +3]X[2* i] *5.0;
}
hored cache
C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa956bd78-6a6b-4d21-a261-f54d0d592293%2F6715b3d4-2c09-465f-8879-ab812fda659d%2Fcg2lod_processed.jpeg&w=3840&q=75)
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- In C++, write a program that outputs the nodes of a graph in a breadth first traversal. Data File: Please use this data file. Text to copy: 100 1 3 -9991 4 -9992 5 -9993 2 -9994 -9995 7 8 -9996 4 7 -9997 -9998 -9999 7 8 -999 Diagram: Also, please take a look at the attached figure on and calculate the weights for the following edges: 0 -> 1 -> 4 0 -> 3 -> 2 -> 5 -> 7 0 -> 3 -> 2 -> 5 -> 8 6 -> 4 6 -> 7 9 -> 7 9 -> 8 To calculates these weights, please assume the following data: 0 -> 1 = 1 0 -> 3 = 2 1 -> 4 = 3 3 -> 2 = 4 2 -> 5 = 5 5 -> 7 = 6 5 -> 8 = 7 6 -> 4 = 8 6 -> 7 = 9 9 -> 7 = 10 9 -> 8 = 11In C++, write a program that outputs the nodes of a graph in a breadth first traversal. Data File: Please use this data file. Text to copy: 100 1 3 -9991 4 -9992 5 -9993 2 -9994 -9995 7 8 -9996 4 7 -9997 -9998 -9999 7 8 -999 Diagram: Also, please take a look at figure 20-6 on page 1414 and calculate the weights for the following edges: 0 -> 1 -> 4 0 -> 3 -> 2 -> 5 -> 7 0 -> 3 -> 2 -> 5 -> 8 6 -> 4 6 -> 7 9 -> 7 9 -> 8 To calculates these weights, please assume the following data: 0 -> 1 = 1 0 -> 3 = 2 1 -> 4 = 3 3 -> 2 = 4 2 -> 5 = 5 5 -> 7 = 6 5 -> 8 = 7 6 -> 4 = 8 6 -> 7 = 9 9 -> 7 = 10 9 -> 8 = 113) Implement the if __name__ == "__main__" : block at the bottom of this file to do the following: 3a) The if main block at the bottom should get the name of the highway graph file from the command line arguments. See the video in Python that explains how to get command line arguments. 3b) Call your parse_highway_graph_file function to parse that file, and to construct a WeightedGraph object from it. 3c) Write some code that outputs (with print statements) the degree of each vertex. You can have one vertex per line, indicating its id (just its 0-based index) followed by its degree. IMPORTANT: Your parse_highway_graph_file function should NOT produce any output. You will have code in your if main block that will have the print statements. The WeightedGraph class has a degree method, inherited from Graph that will return to you the degree of a vertex.
- def f(x,v): return -x**3+5*x**2-8*x+4-(v**2)*(2-x) Define v_list = np.linspace(0, 0.5, 6) and write a for loop to iterate over this list to plot the function f(x, v) for each v value in the list Your plot range of x should be between 0.8 and 2.5. Show all the graphs on the same plot; do not do plot a separate plot for each v value. v_list = np.linspace(0, 0.5, 6) x = np.linspace(0.8, 2.5) for v in v_list: plt.plot(v, f(x,v)) plt.xlim(0.8,2.5) plt.show() ı could not find error here?Consider the following function:int mystery(NodeInt32* node){int counter = 0; while (node != NULL) {counter++;node = node->next; } return counter;}1. Implement a function insertBook(Book newBook) to add a book at the end of thelinked list.a. Ask the librarian to input all the necessary book information.b. Use the information to create a Book objectc. Pass through the Book object as the parameter to the functiond. Store the Book object into the Node objecte. “Link” the object with the rest of the linked list2. Implement a function insertBefore(Book newBook, int bookID) to add a book infront of another book given its bookID.a. Ask the librarian to input all the necessary book information.b. Use the information to create a Book objectc. Pass through the Book object and bookID as the parameter to the functiond. Search for the matching Book objecte. Store the Book object into the Node objectf. “Link” the object with the rest of the linked list3. Implement a function searchBook(int bookID) to search for a book by its bookIDcode and return the book object.a. Ask the librarian to input the bookID.b. If the book doesn’t exist display an…
- Consider the infix expression exp = ( ( 8 / 2 ) + 3 ) * 1 to solve the questions given below: a: Trace the process of converting the infix expression into It's postfix form. b: Evaluate the postfix expression you obtained in part a. *************************************************************************************** Note: Solve the question in your notebook. Draw two tables as shown below. Scan or take a picture, upload the file. a: Next token Action Content of stack Postfix expression b: Next token Action Content of stackPP 12.7 Use stacks to implement a postfix-to-infix translator. Until the user closes the programme, it should repeatedly read a postfix expression and output the equivalent infix expression. If the postfix expression entered is incorrect, throw an exception. PP 12.8 Create the ReverseWords class, which outputs user-inputted elements in reverse order using a stack.Consider the following function:int mystery(NodeInt32* node){int counter = 0; while (node != NULL) {counter++;node = node->next; } return counter;}(a)The mystery function is recursive.A. True B. False
- Write a function sort_and_return_in_pairs_list for example:[12, 13, 11, 15] return =>(11.12) and (12,13)[14,19,16,18,17,15] return =>(14.15) (16.17) (18.19)SOLVE THE MAZE FUNCTION USING STACK.PLEASE ONLY C CODE,DONT USE C++ AND C#. /* R\C 0 1 2 3 4 5 6 7 *//* 0 */ {0, 0, 0, 1, 0, 0, 0, 0},/* 1 */ {0, 1, 1, 1, 0, 0, 1, 0},/* 2 */ {0, 1, 0, 1, 0, 0, 1, 0},/* 3 */ {0, 1, 0, 1, 1, 1, 1, 0},/* 4 */ {0, 1, 0, 0, 0, 0, 1, 1},/* 5 */ {0, 1, 1, 0, 1, 1, 1, 0},/* 6 */ {0, 0, 0, 0, 1, 0, 0, 0},/* 7 */ {0, 0, 0, 0, 1, 0, 0, 0}, #include <stdio.h>#include <stdlib.h>#include <string.h> typedef struct LINKED_STACK_NODE_s *LINKED_STACK_NODE; typedef struct LINKED_STACK_NODE_s{LINKED_STACK_NODE next;void *data;} LINKED_STACK_NODE_t[1]; typedef struct LINKED_STACK_s{LINKED_STACK_NODE head;int count;} LINKED_STACK_t[1], *LINKED_STACK; typedef struct{int R;int C;} POS_t[1], *POS; LINKED_STACK stack_init();void stack_free(LINKED_STACK stack);void stack_push(LINKED_STACK stack, void *data);void *stack_pop(LINKED_STACK stack);void *stack_top(LINKED_STACK stack);int is_empty(LINKED_STACK stack); int is_empty(LINKED_STACK stack){return…Solve the maze function using stack.PLEASE ONLY C CODE, DONT USE C++ AND C# . /* R\C 0 1 2 3 4 5 6 7 *//* 0 */ {0, 0, 0, 1, 0, 0, 0, 0},/* 1 */ {0, 1, 1, 1, 0, 0, 1, 0},/* 2 */ {0, 1, 0, 1, 0, 0, 1, 0},/* 3 */ {0, 1, 0, 1, 1, 1, 1, 0},/* 4 */ {0, 1, 0, 0, 0, 0, 1, 1},/* 5 */ {0, 1, 1, 0, 1, 1, 1, 0},/* 6 */ {0, 0, 0, 0, 1, 0, 0, 0},/* 7 */ {0, 0, 0, 0, 1, 0, 0, 0}, void solve_maze(){int M[8][8] = {/* R\C 0 1 2 3 4 5 6 7 *//* 0 */ {0, 0, 0, 1, 0, 0, 0, 0},/* 1 */ {0, 1, 1, 1, 0, 0, 1, 0},/* 2 */ {0, 1, 0, 1, 0, 0, 1, 0},/* 3 */ {0, 1, 0, 1, 1, 1, 1, 0},/* 4 */ {0, 1, 0, 0, 0, 0, 1, 1},/* 5 */ {0, 1, 1, 0, 1, 1, 1, 0},/* 6 */ {0, 0, 0, 0, 1, 0, 0, 0},/* 7 */ {0, 0, 0, 0, 1, 0, 0, 0},};int I, J, R = 0, C = 3;LINKED_STACK stack;POS pos = (POS)malloc(sizeof(POS));int flag;stack = stack_init(); do{// TODO: Fill this block.} while (R != 7 && C != 7 && R != 0 && C != 0);}int main(){solve_maze();return 0;}
