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10 kN/m 10 kN/m 10 kN/m 10 kN/m 5 kN/m 5 kN/m 5 kN/m Il llir l V 3 m 31 2m 3 m 2 m 3 m 15 m 3m 2 m 15 m 2 m * * SH В D C E

10 kN/m 10 kN/m 10 kN/m 10 kN/m 5 kN/m 5 kN/m 5 kN/m Il llir l V 3 m 31 2m 3 m 2 m 3 m 15 m 3m 2 m 15 m 2 m * * SH В D C E

Solid Waste Engineering
Solid Waste Engineering
3rd Edition
ISBN:9781305635203
Author:Worrell, William A.
Publisher:Worrell, William A.
Chapter4: Mechanical Processes
Section: Chapter Questions
Problem 4.16P
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CAN YOU PLEASE ANSWER THIS PROBLEM I NEED TODAY ASAP THANK YOU! SAMPLE PROBLEM given in second image
-137 M/ME AN By PATIO 4 PROPORTION P ; P. 44 A AB 1 FEM 10.8 BAL 10.86 030 BAL 0.30 co 0.64 BAL 4 0.00 BAL 0.00 -0.16 T BAL 0:16 Find Moment 0.00 304/ an PA BV, RA () +8:10 = 3(3)(1-5 +5) A = 5.5A/ F: +1 PA + BV, 3(3) Bu, 3.41 + 3 kiet Menter E DF 1 433 P 00 00 DO ANY VE 8:20 d alm K 03070692 464 23 060-134 34138 437287 0.15 0.34 0.15 0.34 0.320.72 0.37 0.72 GONG.CO -0.000.00 630-4.39 . C CR 1 235 235 067 9.67 14 1.A 411 0.17 431 0.30 0.00 ww UTILININE THE FORMULA ܠܐ ܝ ܐ ܠܦܠܦܐ 3.15 -10 BC ALA refers · [(x² (1x). FEM B 10. " Pab²". (" (14/3-1/6+2)(x) (4032 10. "(16/3-44x) (x)² (4-x) = FEM BC -=[ P=²b [ (14)-4+) ( AUAW FOMBA Leg 1/2 (4) (3) (1/3 <3 + 1) = R₂ (A) +819 Rc = 0.9525 # BV₂+F₂= 1/2 (4) (3) BV₂ = 5.0475 (4-x)²₂ -27 = 2.5s = Rg BV, +BV₂ = 8-4575/
Transcribed Image Text:-137 M/ME AN By PATIO 4 PROPORTION P ; P. 44 A AB 1 FEM 10.8 BAL 10.86 030 BAL 0.30 co 0.64 BAL 4 0.00 BAL 0.00 -0.16 T BAL 0:16 Find Moment 0.00 304/ an PA BV, RA () +8:10 = 3(3)(1-5 +5) A = 5.5A/ F: +1 PA + BV, 3(3) Bu, 3.41 + 3 kiet Menter E DF 1 433 P 00 00 DO ANY VE 8:20 d alm K 03070692 464 23 060-134 34138 437287 0.15 0.34 0.15 0.34 0.320.72 0.37 0.72 GONG.CO -0.000.00 630-4.39 . C CR 1 235 235 067 9.67 14 1.A 411 0.17 431 0.30 0.00 ww UTILININE THE FORMULA ܠܐ ܝ ܐ ܠܦܠܦܐ 3.15 -10 BC ALA refers · [(x² (1x). FEM B 10. " Pab²". (" (14/3-1/6+2)(x) (4032 10. "(16/3-44x) (x)² (4-x) = FEM BC -=[ P=²b [ (14)-4+) ( AUAW FOMBA Leg 1/2 (4) (3) (1/3 <3 + 1) = R₂ (A) +819 Rc = 0.9525 # BV₂+F₂= 1/2 (4) (3) BV₂ = 5.0475 (4-x)²₂ -27 = 2.5s = Rg BV, +BV₂ = 8-4575/
10 kN/m 10 kN/m 10 kN/m 10 kN/m kN/m 5 kN/m 5 kN/m Indi muffine sull 2 3 m 2 m 1.5 m 1.5 m 31 3 m 2 m 2m 3 m B Me = 7.5 pts Mc = 7.5 pts RA = 7.5 pts Ro= 7.5 pts D
Transcribed Image Text:10 kN/m 10 kN/m 10 kN/m 10 kN/m kN/m 5 kN/m 5 kN/m Indi muffine sull 2 3 m 2 m 1.5 m 1.5 m 31 3 m 2 m 2m 3 m B Me = 7.5 pts Mc = 7.5 pts RA = 7.5 pts Ro= 7.5 pts D
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