Question
Asked Oct 17, 2019

The four 1.0 g spheres shown in the figure are released simultaneously and allowed to move away from each other.

What is the speed of each sphere when they are very far apart?
Express your answer with the appropriate units.
10 nC
10 nC
+
1 em
cm
+
10 nC
10 nC
+
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10 nC 10 nC + 1 em cm + 10 nC 10 nC +

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Expert Answer

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Step 1

As shown in the figure, the potential energy of the system is,

Since the charge of the four spheres is equal and substitute the values,

49. 44, , 9,Я, 99, 99, , 94,
+
U=k
+
+
а
2а 2а
а
а
а
+2
-
10 C
10°с
(10 лC)
(10пС)
1лС
1пС
-(ох10'м m'/с")
+2
10? ш
10? ш
(1сm)
1ст
1сп
48.72X10J
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49. 44, , 9,Я, 99, 99, , 94, + U=k + + а 2а 2а а а а +2 - 10 C 10°с (10 лC) (10пС) 1лС 1пС -(ох10'м m'/с") +2 10? ш 10? ш (1сm) 1ст 1сп 48.72X10J

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Step 2

The kinetic energy of the four spheres is,

Substitute the values,

KE 4
10kg
KE-2(1.08)
1g
-(2x10*ke)v
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KE 4 10kg KE-2(1.08) 1g -(2x10*ke)v

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Step 3

According to the law of con...

(2x10 kg)v48.72x10*
48.72x10
2x10kg
0.49m/s
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(2x10 kg)v48.72x10* 48.72x10 2x10kg 0.49m/s

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