+10.0X10 2 -8.0X10-C Charges q1 = q2 = +10.0x10-4C and q3 =-8.0×10-4C are distributed as shown on the right. 1) What is the electric field vector at point C? Remember: magnitude and direction! 2) What is the value of V at point C? (2)2 =F1.8N/CI =D118NK dawnwerd disection 2.0 m 2.0 m C 2) rer) = -Ex Ax 2.0 m = (18N/<) C2m) 3.6 %3D 93

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter19: Electric Forces And Electric Fields
Section19.6: Electric Field Lines
Problem 19.5QQ: Rank the magnitudes of the electric field at points A, B, and C in Figure 19.19 (greatest magnitude...
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+10.0X10-2
-8.0x10-
Charges q1 = q2 = +10.0x10-4C and q3 =-8.0x10-4C are distributed as shown on the right.
1) What is the electric field vector at point C? Remember: magnitude and direction!
2) What is the value of V at point C?
) E =
72)2
=F1.8N/C!
= 1.8 NC downwand direction
2.0 m
2) ver) = -Ex 4x
2.0 m
3.6
93
Transcribed Image Text:+10.0X10-2 -8.0x10- Charges q1 = q2 = +10.0x10-4C and q3 =-8.0x10-4C are distributed as shown on the right. 1) What is the electric field vector at point C? Remember: magnitude and direction! 2) What is the value of V at point C? ) E = 72)2 =F1.8N/C! = 1.8 NC downwand direction 2.0 m 2) ver) = -Ex 4x 2.0 m 3.6 93
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