100 kN 64 kN 82 kN 82 kN 55 kN 2m A 3 m 3m 3 m 3 m 3m 3 m 91 kN 73 kN 46 kN

Q: 4 kN RA = 64 kN 30 kN/m 2.0 m 2.5 m MA = 70 kN.m %3D

A:

Q: 40 kN 30 kN 20 kN 16 kN-m 24 kN/m 10 kN/m A 15 kN 3 m 4 m 2 m 4 m 2m 1.5 m

A: Loads acting on a beam is given. Dimensions at which loads acting and the magnitudes of the load are…

Q: 3 m 2 m B 4 m F A 30 kN 18 kN

A:

Q: 4 kN/m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 2 kN/m 4 kN

A: Given data:

Q: في الشكل أدناة أوجد محصله القوتين واتجاهها 200 kN 2 150 kN 4 3.

A: The FBD of the force acting is given below,

Q: 50 KN 100 KN/m 60 KN/m 40 KN/in 10 KN.m 2.0 m 6.0 m 2.0 m 4.0 m

A:

Q: A Mansard roof truss is loaded as shown. Determine the force in members GI, HI, and HJ.

A: Given data To determine the forces in the members GI,HI and HJ

Q: 2.8 m 40° 4.7 KN 2.7 m B 4.7 KN E BC=CD 2.7 m

A: A truss is a structural member, used to create rigid structures. The primary function of the truss…

Q: 40 kN E 2 m B F 3 m 50

A: to find reaction component at B and C

Q: 38.3 kN-m F) 23.3 kN-m G 8.3 kN-m H. 13.8 kN-m E.

A:

Q: 15 kN 10 kN 12 kN/m 8 kN/m A C. D 3 m 2 m 3 m El is constant

A: configuration diagram:

Q: G 1 m H 2 m |C -2 m 2 m -2 m- -2 m 10 kN 15 kN 30 kN

A: Calculate the reaction at the support, RA+RE=10+30+15RA+RE=55   ....... (1)Taking moment about…

Q: 200 kN 100 kN 100 kN в F 30° 60° 60° 60 60° 30° A G 2 m 2 m 2 m 50 kN 50 kN

A:

Q: 12 kN.m 3 m 12 kN/m 1 m 12 kN.m 1 m 4 m 3 m 12 kN/m

A: The shear force and bending moment diagram has been drawn below.

Q: 15 kN 20 kN 2 m m

A:

Q: Shean (kN/m q = 50 kN/m2 %3D = 50 kN/m2 (+50 C = 50 kN/m2

A: given:

Q: 100 kN 50 mm 50 mm 75 mm 75 mm 40 kN 30° 400 mm

A:

Q: a. 24 kN 3 m 7 kN/m B 90 kN-m 6 m V max M max 3m D 3 m 12 kN X E

A: First calculate the reactions the. Draw the sfd and bmd

Q: 2 kN 2 kN 2 kN/m 3 kN/m B 3.5 m 15 m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: F1 = 5 kN F2 13 kN -30 C. F3 = 4 kN 45 A 2m 7 m 5n F4 = 22 kN a30° F5 = 4 kN

A:

Q: 2 KN/m 2 KN/m 3 m 3 m R R2

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 20 kN 12 kN A В M = 10 kN-m %3D 4m 4m 4m Figure Q1 (b)

A:

Q: 2 kN 50 mm 5 kN• m D 80 mm B C 1.0 m 1.0 m 1.0 m

A:

Q: F B 4 m 4 m 4 m 4 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 18 kN 3 B 25 kN 8m DE 6m D 10 kN Figure 1

A:

Q: 100 lb 30° 200 lb 2 ft 300 ft-lb 2 ft 2 ft 2 ft-

A: First we resolved 100 lb force, and calculated horizontal force, vertical force and moment due to…

Q: 15 KN 10 KN 10 KN 20 KN E A 5.0m

A: To determine the support reaction at J.

Q: 1.5 m 4 kN A B 2 m 8 kN C D 2 m F E

A: Let  RFx and RFy are the horizontal and vertical reaction at F RE is vertical reaction at E By using…

Q: 4 m A) 12 kN.m B) 16 kN m C) 20 kN m D) 22 kN.m 4 KN co 2 m 10 kN 2 m 2 m 2 kN/m E

A:

Q: 96 30 lb/ft 180 Ib · ft - 9 ft - 4.5 ft M (lb · ft) 200

A:

Q: 80 kN 40 kN 60 kN -10 kN/m A B 2 mim. 3 m 3 m 2m 1 m (b) 10 k I k/ft B 12 8' (b)

A:

Q: 10 m 10 m 10 m 10 m 180 KN 8 150 KN 11 4 7 10 5 9. 12 12 m 1 3 6 14 20 m 13 200 KN 2 A

A:

Q: 2 KN/m 2 KN/m URN A 30 3.0m 3m 2.0m 2.0 m 4,0 m

A: There are three different types of loads are there on this beam which are Uniformly varying,…

Q: F 105° 60° 45° 300 lb 60° 400 lb 200 lb

A:

Q: 8 KN 3 AN/m 12 AN 6 KN/m BC D 2.0 m 1.0m 3.0 m 3.0 m

A: Apply the equilibrium condition of force in the vertical direction. Apply the equilibrium condition…

Q: F1 = 5 kN F2 = 13 kN 0 = 45° B = 60° C F3 = 4 kN A B 4 m 8 m F4 = 22 kN 6m

A: given:

Q: 3m 6 m -3 m G 20 kN 15 kN H. B -3 m 3 m

A: given; ED=3mCE=4mCH=6mHF=4mFD=9mlets taking tension force in member BC=TBClets taking tension force…

Q: 6 kN/m 4 kN/m 2 kN/m ]B 4 m 6 m Fig (2)

A:

Q: -5 at 3 m = 15 m- 12 kN 12 kKN |M IN 12 kN 12 kN 12 kN 12 kN L 20 kN– 4 m 40 kN- G 4 m 40 kN- 4 m 40…

A: The free-body diagram of the structure is shown as

Q: (4) 18 kN 4 kN/m B 6 m -2 m

A: Question 4) is a propped cantilever beam

Q: 2 kN/m 10 kN t. 5 m 3 m 2 m Figure 2

A:

Q: C 30 kN 50 kN 70 kN 50 kN d=20 mm d=40 mm 1m 2 m 1m

A: draw FBD of each section and find stresses.for solution refer below image.

Q: 15 KN 18 kN 40 kN/m 3 m 6 m 4 m Fig.

A: To draw the SFD and BMD and determine the maximum bending moment

Q: 50 kN 500 40 kN 30 kN 50 mm. 200 mm 200 mm 50 mm 250 mm 30 kN

A:

Q: 100 kN I 120 kN/m 60 kN/m Ic D 315 kN-m 3 m 3 m 3 m 3 m

A: Draw the free-body diagram of the beam.

Q: F = 375 N F2 = 500 N 5 3 В. 0.5 m 8 m 6 m - 5 m- 370 F3 = 160 N

A: The given system of forces is as shown below,

Q: 20 KN 40 kN/m 150 kN m 3m

A: According to the company's guidelines when multiple questions are asked in a single request,  only…

Q: F3 = 52 lb 13 12 F1 = 80 lb 25°

A: Given that, The component of forces in the x-direction,

Q: 3.kN 30 kN/m B.

A: given; upper left beam; ⇒lets take reaction force at A=RA⇒lets take reaction force at B=RB⇒load…