8 KN 3 AN/m 12 AN 6 KN/m BC D 2.0 m 1.0m 3.0 m 3.0 m

Q: 3 m 2 m B 4 m F A 30 kN 18 kN

A:

Q: y F2 = 500 N F = 600 N 3 A 35° 4 0.1 m 0.2 m- 0.3 m F3 = 800 N B -0.4 m

A:

Q: 4 kN/m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 20 KN 10 KN 10KN/m 15KN/m 10 KN/m B. 1.00 1.00 2.00 1.00

A:

Q: 6 kN/m 20 kN 90 mm В C h 2.4 m -1.2 m –

A: Solution: To calculate support reactions Under static equilibrium RA+RB=6kN×2.4+20=34.4kN Taking…

Q: 2 kN/m 4 kN

A: Given data:

Q: -1.2 m 0.1 m 0.3 m В |C 0.6 m A

A: Replacing support at A and with the tension in the rope and in member BC, below given is the Figure.…

Q: 2 m C 2.5 m 125 mm 1.5 m 25 kN/m 2 m 4 m

A: To determine the reaction at A and B, the beam can be dealt in two sections that are AD and DB. In…

Q: 50 KN/m 120 KN.m B- 9m 4m

A: For solution refer below images.

Q: 50 KN 100 KN/m 60 KN/m 40 KN/in 10 KN.m 2.0 m 6.0 m 2.0 m 4.0 m

A:

Q: 38.3 kN-m F) 23.3 kN-m G 8.3 kN-m H. 13.8 kN-m E.

A:

Q: 5 m A 30 kN B 5 m 5 m 5 m 5 m 20 KN 5 m 5 m E

A:

Q: F1 = 5 kN F2 = 13 kN 0 = 45° B - 60° C F3 = 4 kN B 2 m 3. 7m F4 = 22 kN E lJa = 30° F5 = 4 kN

A: In case of multiple force on a system, resolve the forces in horizontal and vertical direction. This…

Q: G 1 m H 2 m |C -2 m 2 m -2 m- -2 m 10 kN 15 kN 30 kN

A: Calculate the reaction at the support, RA+RE=10+30+15RA+RE=55   ....... (1)Taking moment about…

Q: H G 60 E D 7 kN 7 kN 9 kN 6m 6m 6m 6m

A:

Q: 12 kN.m 3 m 12 kN/m 1 m 12 kN.m 1 m 4 m 3 m 12 kN/m

A: The shear force and bending moment diagram has been drawn below.

Q: 50KN 20 kN 1OKN/M 3m 1m 2 m Figure 1

A: Given

Q: 40 kN/m B 8 m 2 m

A: Linear deviation of the longitudinal axis of the beam is known as deflection whereas angular…

Q: 2 kN 2 kN 2 kN/m 3 kN/m B 3.5 m 15 m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: F1 = 5 kN F2 13 kN -30 C. F3 = 4 kN 45 A 2m 7 m 5n F4 = 22 kN a30° F5 = 4 kN

A:

Q: 3 kN 12 kN.m 3 kN / m 5 kN / m 7 3 m 3 m 2 m

A: given:

Q: 150 mm y30 mm 120 mm Area 2 X2 30 + (2b/3) 100 mm X3 = 150- (4r/3n) Area1 y2 TArens y3 120 mm 130 mm

A:

Q: 2 kN 50 mm 5 kN• m D 80 mm B C 1.0 m 1.0 m 1.0 m

A:

Q: F B 4 m 4 m 4 m 4 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: y -9 cm- -3 cm 2 cm 19 cm 2 cm C 15 cm 9 cm- 3 cm→

A: Divide given figure in 3 section/shape,

Q: 15 KN 10 KN 10 KN 20 KN E A 5.0m

A: To determine the support reaction at J.

Q: 100 kN 64 kN 82 kN 82 kN 55 kN 2m A 3 m 3m 3 m 3 m 3m 3 m 91 kN 73 kN 46 kN

A:

Q: f= 1000 N/m A E+ < << - 0.7 m 0.4 m

A:

Q: Ax= 3 points 800 N 200 N.m 30 - 6 m -2 m 360. 8 N →

A:

Q: 2 tór/m 8 ton F 4 ton-m E 3 ton/m 2 m 4 m Im1m 2 m 2 m

A: According to the principal of engineering mechanics  Reaction and moment at support is equal to zero

Q: 24 kN/m 64 kN • m D A B - 2 m -2 m

A: Let us draw the reaction force

Q: 80 kN 40 kN 60 kN -10 kN/m A B 2 mim. 3 m 3 m 2m 1 m (b) 10 k I k/ft B 12 8' (b)

A:

Q: 6 m 6 m 4 m A

A:

Q: 2 KN/m 2 KN/m URN A 30 3.0m 3m 2.0m 2.0 m 4,0 m

A: There are three different types of loads are there on this beam which are Uniformly varying,…

Q: A 1.20m 18 KN 0.75m 12 kN/m 1.20m B

A: The given is as shown below,

Q: 2 KN 20 20 5 KN X 45° D F 2 KN

A:

Q: 15 kN 30 kN-m Figure 2 ID в 1.5 m 3 m 1.5 m

A: The fixed support resists all the moments that is translational motion and the rotational motion of…

Q: 125 kN 50 kN/m VIIE A C 3 m 12 m

A:

Q: 3m 6 m -3 m G 20 kN 15 kN H. B -3 m 3 m

A: given; ED=3mCE=4mCH=6mHF=4mFD=9mlets taking tension force in member BC=TBClets taking tension force…

Q: 120 kN 7.5 kN/m 417.5 kNm 282.5 kNm A D 5 m 5 m 10 m- RA = 115.5 kN Rg = 79.5 kN

A: Shear force diagram represents shear force at every section of the beam. Shear force at any…

Q: 1.0 m 2.0 m 05 m 05 m 20 kN 4 KN 10 kN 4.0 m

A: Given Data: Force (F) = 10 kN

Q: 6 kN 2.5m

A: Write the equilibrium condition for the above problem.

Q: З KN 8 kN A 25 kN m 2 m 2 m 2 m 5 kN

A: Note: As per bartleby guidelines for more than one question asked only one question to be solved…

Q: (4) 18 kN 4 kN/m B 6 m -2 m

A: Question 4) is a propped cantilever beam

Q: 5 kN 4 m B 5 kN 4 m C D 2 m

A: The free-body diagram of the strut is given as,

Q: C 30 kN 50 kN 70 kN 50 kN d=20 mm d=40 mm 1m 2 m 1m

A: draw FBD of each section and find stresses.for solution refer below image.

Q: 15 KN 18 kN 40 kN/m 3 m 6 m 4 m Fig.

A: To draw the SFD and BMD and determine the maximum bending moment

Q: G. 620mm 1.8m 1.2m

A: As per honor code and answering guidelines I can answer 1st 3 sub parts at a time.So i answered…

Q: 20 KN 40 kN/m 150 kN m 3m

A: According to the company's guidelines when multiple questions are asked in a single request,  only…

Strain energy

The term strain indicates the variation in an object's length, area, and volume when the object is subjected to an external force. The external force may be of normal, shear, moment, torque, etc. The strain in an object depends on the types of external force and cross-section of the object. Mathematically, the evaluation of strain can be obtained with the help of elastic constants.