11) Drawing (1) shows a nonequilibrium system comprised of pure water separated from an aqueous solution by a semipermeable membrane which permits water molecules to pass through it, but not solute molecules. Shaded spheres represent solute particles and unshaded spheres represent water molecules. Which drawing (2)-(5) represents this system after equilibrium is reached? 11) (1) (2) (3) (4) (5) A) drawing (2) B) drawing (3) C) drawing (4) D) drawing (5)

11) Drawing (1) shows a nonequilibrium system comprised of pure water separated from an aqueous solution by a semipermeable membrane which permits water molecules to pass through it, but not solute molecules. Shaded spheres represent solute particles and unshaded spheres represent water molecules. Which drawing (2)-(5) represents this system after equilibrium is reached? 11) (1) (2) (3) (4) (5) A) drawing (2) B) drawing (3) C) drawing (4) D) drawing (5)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.16QAP

See similar textbooks

Similar questions

the dimensionless Henry's law constant for trichloroethylene at 25 degrees Celcius is 0.4. A sealed glass vial is prepared that has an air volume of 4ml overlying an aqueous volume of 36ml. TCE is added to the aqueous phase so that initially it has an aqueous-phase concentration of 100 ppb. After the system equilibrates, what will be the concentration (in units of microgram per liter) of TCE in the aqueous phase
Drug: C20H22ClN (Flexeril also known as iCyclobenzaprine HCl Using unit analysis, clearly show the set-ups for your calculations. You wish to prepare 50.0 mL of 2.30 x 10–2 M solution of your drug. (hint-how many grams will you need of your drug?) Describe how to prepare this solution from the pure drug and deionized water. Analytical balances and volumetric flasks are available to you. (Assume that your drug dissolves in water, at least to the extent necessary for this problem.) Use complete sentences in your description of the solution preparation process. A patient is given 2.0mL of a 3.00% (m/v) solution of your drug, how many milligrams of the drug did they receive? What is the molarity of a 3.00% (m/v) solution of your drug?
A solution is prepared by dissolving 40.00 g of MgCl2 (f.w. = 95.211 g mol–1), a non-volatile solute, in enough water (m.w. = 18.02 g mol–1) to result in exactly 2 L of solution at 25 °C. Assume the density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Determine the freezing point of the solution.
Q3 / The solubility of sodium chloride NaCl in water at 290 Kis 35.8 kg / 100 kg of water. Express the solubility as the following: 1. Mass fraction and the mass percent of Naci 2. Mole fraction and mole percent of NaCl 3. kmol of NaCl per 1000 kg of water Note: molecular weight of NaCl = 135.8, and water = 18.016
What volume (mL) of the prepared low alcoholic elixir is needed if the prescription requires 120 mL of an alcoholic elixir with 35% v/v alcoholic strength? Low alcoholic elixir alcoholic strength: 20% Low Alcoholic ElixirCompound Orange Spirit 10mLAlcohol 100mLGlycerin 200mLSucrose 320gPurified water, qs ad 1000mL High alcoholic elixir alcoholic strength: 79% High Alcoholic ElixirCompound Orange Spirit 4mLSaccharin 3gGlycerin 200mLAlcohol, qs ad 1000mL a 30.51 mL b 119.39 mL c 89.49 mL d 30.61 mL
A solution of potassium phosphate contains a mixture of 164 mg of monobasic potassium phosphate (MWt: 136) and 158 mg of dibasic potassium phosphate (MWt: 174) per milliliter. If a hyperalimentation fluid calls for the addition of 45 mEq of potassium, how many milliliters of the solution should be used to provide this level of potassium? How many millimoles of total phosphate will be represented in the calculated volume of potassium phosphate solution?
Hexanoic acid was added to an immiscible biphasic solvent system, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D2) of hexanoic acid in water with respect to CCl4.
An excess amount of Ba(NO3)2 was added to 2 liters of water at 25 oC until the solution is saturated. Because Ba(NO3)2 is only slightly soluble in water, the excess Ba(NO3)2 was filtered out to get a solid-free mixture. The proponents of the experiment thought about using the concept of colligative properties, specifically boiling point elevation, to determine Ksp. It was observed in their experiments that the solution boils at 100.15 deg C. Kb of water = 0.51 K-kg/mol. Barium nitrate dissociates using: Solve the ff: a) Amount of Ba(NO3)2 dissolved in grams. MW of Ba(NO3)2 = 261.3 g/molb) Solubility product, Kspc) Vapor pressure of the solution in kPa
Use E5C.1(a) to Plot the data in excel. Place two data sets on the same graph: one for temp vs. x and one for temp vs y (remember, x and y are the mole fractions and they belong on the x-axis). Don’t forget to include the boiling points of the pure substances – they are data, too. Add a trendline (polynomial, 3rd order should work) to each of the coexistence lines separately. Scale the plot appropriately and use the graph to answer the questions. Then complete E5C.1(b)
A 100-liter empty jar was spiked with 20 mg of TCE (C2HCl3) under room temperature condition. The jar was then closed tightly. What is the concentration (in atm.) of TCE in the air at 25 C? (TCE: MW: 131.4 g/mol; TCE solubility in water (Cs) = 1100 mg/L; Pv (pure liquid at 25oC) = 10^-1.01 atm. KH = 10^1.03 L atm mol-1; KOW = 102.42). if the jar was half filled with water and half filled with air, what were the concentrations of TCE in both air and water at 25C?
Although other solvents are available, dichloromethane(CH₂Cl₂) is still often used to “decaffeinate” drinks because thesolubility of caffeine in CH₂Cl₂ is 8.35 times that in water.(a) A 100.0-mL sample of cola containing 10.0 mg of caffeine is extracted with 60.0 mL of CH₂Cl₂. What mass of caffeine re-mains in the aqueous phase? (b) A second identical cola sampleis extracted with two successive 30.0-mL portions of CH₂Cl₂.What mass of caffeine remains in the aqueous phase after each extraction? (c) Which approach extracts more caffeine?
Hexanoic acid was added to an immiscible biphasic solvent sysem, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D1) of hexanoic acid in CCl4 with respect to water.